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91Ó°ÊÓ

Calculate each of the limits in Exercises 49-64. Some of these limits are made easier by considering the logarithm of the limit first, and some are not.

limx→∞xlnx.

Short Answer

Expert verified

The exact value of the limitlimx→∞xlnxis,1.

Step by step solution

01

Step 1. Given information

limx→∞xlnx.

02

Step 2. Taking logarithm of the limit.

limx→∞lnxlnx=limx→∞(lnx)ln(x)=limx→∞(lnx)2

The limit using L'Hopital's rule is given below:

limx→∞(lnx)2=limx→∞(lnx)3lnx [ in the form of ∞∞]

=limx→∞3(lnx)2·1x1x[L'Hopital's rule]

=limx→∞3(lnx)2·1x2=3limx→∞(lnx)2x2

=3limx→∞2(lnx)·1x2x [ Using L'Hopital's rule]

=3limx→∞(lnx)x2

=3limx→∞1x2x [ L'Hopital's rule]

=3limx→∞12x2=32·1∞=0

03

Step 3. Therefore, the value of the limit is given by,

limx→∞xlnx=e0=1

Therefore, the exact value of the limit is,1.

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