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91Ó°ÊÓ

Use a sign chart for f'to determine the intervals on which each function fis increasing or decreasing. Then verify your algebraic answers with graphs from a calculator or graphing utility.

f(x)=3x+1x2-1

Short Answer

Expert verified

Ans:

Intervals of the given function are(-∞,-13]∪[-13,∞)

Always Decreasing function.

Step by step solution

01

Step 1. Given information:

f(x)=3x+1x2-1

02

Step 2. Finding the derivative of the function:

f(x)=3x+1x2-1f'(x)=(x2-1)(3)-(3x+1)(2x)x2-12∂∂xuv=v∂∂x(u)-u∂∂x(v)v2f'(x)=3x2-3-6x2-2xx2-12=-3x2-2x-3x2-12letf'(x)=0∴-3x2-2x-3x2-12=0⇒-3x2-2x-3=x2-12⇒-3x2-2x-3=x4-2x2+1⇒x4+x2+2x+2x=-13

03

Step 3. Inserting the root points on the number line(Sign chart):

After inserting the root values we can find the increasing and decreasing intervals of the given function.

Intervals of the given function are(-∞,-13]∪[-13,∞)

Always Decreasing function.

04

Step 4. Verifying algebraic answers with graphs :

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