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In Exercises 63–72, set up and solve a definite integral to find the exact area of each surface of revolution obtained by revolving the curve y = f(x) around the x-axis on the interval [a, b].

f(x)=3x+1,[a,b]=[0,3]

Short Answer

Expert verified

The exact area of the surface of the revolution obtained by revolving the curvef(x)=3x+1 around the x-axis on the interval 0,3isπ18343-1313.

Step by step solution

01

Step 1. Given Information.

The given curve is f(x)=3x+1and the interval is0,3.

02

Step 2. Find the exact area.

To find the area, we will use the formula of surface area as a definite integral which isS=2π∫abf(x)1+(f'(x))2dx.

So,

S=2π∫033x+11+323x+12dxS=2π∫033x+11+943x+1dxS=π∫0312x+13dxS=π2312x+1332·11203S=π184932-1332S=π18343-1313

Thus, the exact area isπ18343-1313.

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