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In Exercises 63鈥72, set up and solve a definite integral to find the exact area of each surface of revolution obtained by revolving the curve y = f(x) around the x-axis on the interval [a, b].

f(x)=x,[a,b]=[0,4]

Short Answer

Expert verified

The exact area of the surface of the revolution obtained by revolving the curvef(x)=x around thex-axis on the interval 0,4isS=61717-1.

Step by step solution

01

Step 1. Given Information.

The given curve is f(x)=xand the interval is0,4.

02

Step 2. Find the exact area.

To find the area, we will use the formula of surface area as a definite integral which isS=2abf(x)1+(f'(x))2dx.

So,

S=204x1+12x2dxS=204x1+14xdxS=041+4xdxS=231+4x321404S=61732-1S=61717-1

Thus, the exact area isS=61717-1.

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