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In Exercises 63鈥72, set up and solve a definite integral to find the exact area of each surface of revolution obtained by revolving the curve y = f(x) around the x-axis on the interval [a, b].

f(x)=x,[a,b]=[0,2]

Short Answer

Expert verified

The exact area of the surface of the revolution obtained by revolving the curve f(x)=xaround the x-axis on the interval0,2is42.

Step by step solution

01

Step 1. Given Information.

The given curve isf(x)=xand the interval isa,b=0,2.

02

Step 2. Find the exact area.

To find the area, we will use the formula of surface area as a definite integral which is S=2abf(x)1+(f'(x))2dx.

So,

S=202x1+(1)2dxS=2202xdxS=2212x202S=42

Thus, the exact area is42.

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