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Use definite integrals to find the volume of each solid of revolution described in Exercises. (It is your choice whether to use disks/washers or shells in these exercises.)

The region between the graph offx=2lnx,y=0,y=3andx=0,revolved around the x-axis.

Short Answer

Expert verified

The required volume by using shells isV≈12.5π.

Step by step solution

01

Step 1. Given Information

We have given a function :-

fx=2lnx

We have to find the volume of region of graph of this function and y=0,y=3andx=0, revolved around the x-axis.

02

Find the integral and evaluate it to calculate volume 

We know that by using shells the volume is given by :-

V=2π∫cdr(y)h(y)dy.

Here axis of revolution is x-axis. So ry=yand height is given by the function h(y)=ey2.

Then we get the volume as following :-

V=2π∫03yey2dy⇒V=2πy22ey2-4ey203⇒V=2π92e32-4e32-0-4⇒V=2π12e32+4⇒V=2πe32+82⇒V≈π4.5+8⇒V≈12.5π

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