/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 56 You may have noticed that even v... [FREE SOLUTION] | 91Ó°ÊÓ

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You may have noticed that even very simple functions give rise to arc length integrals that we have no idea how to compute. In Exercises 53–56, use a graphing calculator to approximate a definite integral that represents the arc length of the given function f(x) on the interval[a, b].

f(x)=lnx,[a,b]=[1,3]

Short Answer

Expert verified

By using a graphing calculator the approximate arc length of the given function on the given interval is2.30199.

Step by step solution

01

Step 1. Given Information.

The given function is f(x)=lnxand the interval is1,3.

02

Step 2. Find the arc length.

We have to use a graphing calculator to approximate a definite integral that represents the arc length of the given function f(x)=lnxon the interval 1,3.

So, the arc length of a function from the given interval is given by ∫ab1+(f'(x))2dx.

Thus, the arc length of the given function on the given interval is role="math" localid="1650700995895" ∫131+1x2dx=∫131+1x2dx

Now, by using the graphing calculator the approximate arc length of the definite integral is∫131+1x2dx≈2.30199.

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