/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 53 You may have noticed that even v... [FREE SOLUTION] | 91Ó°ÊÓ

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You may have noticed that even very simple functions give rise to arc length integrals that we have no idea how to compute. Use a graphing calculator to approximate a definite integral that represents the arc length of the given function f(x) on the interval [a, b].

f(x)=x3,a,b=-1,1

Short Answer

Expert verified

The approximate value is3.0957.

Step by step solution

01

Step 1. Given information.

Consider the function isf(x)=x3,a,b=-1,1.

02

Step 2. Use arc length formula.

The formula for a function to find the arc length fromx=atox=bis given by∫ab1+f'x2dx.

03

Step 3. Find definite integral for the given function.

Substitute corresponding values into the arc length formula.

∫ab1+f'x2dx=∫-111+ddxx32dx=∫-111+3x22dx=∫-111+9x4dx

04

Step 4. Use graphing calculator.

Find the approximate value of definite integral ∫-111+9x4dxwith the help of graphing calculator.

∫-111+9x4dx≈3.0957

The area under the definite integral between the interval -1,1in the graphing calculator is represented as follows.

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