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Consider the region between f(x)=(x-2)2and g(x) = x on [1, 4]. For each line of rotation given in Exercises 45鈥48, use the shell method to construct definite integrals to find the volume of the resulting solid.

Short Answer

Expert verified

The integral can be given as 214(-x3+4x2+x-4)dx

and the value of integral is31.5cubicunits

Step by step solution

01

Given information

We are given functionsf(x)=(x-2)2andg(x)=x

also

02

Find the integral and evaluate it

We know that integral can be given as V=2abr(x)h(x)dxthe axis of rotation is r(x)=x+1and the height can be given as h(x)=x-(x-2)2

Substituting the values in the integral we get,

role="math" localid="1650687932200" V=214(x+1)(x-(x-2)2)dxV=214(-x3+4x2+x-4)dxV=2[-x24+43x3+x22-4x]41V=2[15.75]V=31.5

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