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Consider the region betweenf(x)=(x-2)2 and g(x) = x on [1, 4]. For each line of rotation given in Exercises 45–48, use the shell method to construct definite integrals to find the volume of the resulting solid.

Short Answer

Expert verified

The integral can be given as

2π∫cd(-y2+yy+y+y+2)dy

And the value of the integral is19.13Ï€.

Step by step solution

01

Given information

We are given functionsf(x)=(x-2)2 and g(x) = x

also we have,

02

Find the integral and evaluate it

We know that the integral can be given as V=2π∫cdr(y)h(y)dyas the axis of rotation is y=-1 the radius can be given as r(y)=(y+1)and the height can be given as h(y)=(y+2-y)

Hence the integral can be given as

V=2π∫cd(y+1)(y+2-y)dyV=2π∫cd(-y2+yy+y+y+2)dyV=2π[-y33+25y52+23y32+y22+2y]41 V=2π[12.8-3.23]V=2π[9.56]V=19.13π

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