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91Ó°ÊÓ

Find each mass described in Exercises 41–48.

The mass of a 10-centimeter rod with square cross section of side length 1 centimeter, made of a combination of metals in such a way that the density of the rod x centimeters from the left end is ÒÏ(x)=15−0.5xgrams per cubic centimeter.

Short Answer

Expert verified

The mass of the rod is 125 grams

Step by step solution

01

Given Information 

The mass of a 10-centimeter rod with square cross section of side length 1 centimeter, with the density of the rod x centimeters is

ÒÏ(x)=15−0.5x

02

Fromula 

Volume of cuboid = length time width times height

The length and height of cuboid is 1 inches and width is ∆x

Volume=lbhV=(1)(1)∆xV=∆x

03

Density 

Let xi represents slice of the rod at some point

The density throughout enter slice is

ÒÏ(xi)=15−0.5xiÒÏ=MV15−0.5xi=M∆xM=∆x15−0.5xi

04

Integration 

The approximate of the entire rod is the sum

∑∆x15−0.5xi

Accumulate the mass from x= 0 to 10 to find total mass

∫01015−0.5xdx=15x-0.5x22010=15(10)-0.5(10)22=125grams

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