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91Ó°ÊÓ

Find each mass described in Exercises 41–48.

The mass of a cylindrical rod with a radius of 3 centimeters and a length of 20 centimeters, made of a combination of copper and aluminum in such a way that

the density of the rod x centimeters from the left end is ÒÏ(x)=8.93−0.015xgrams per cubic centimeter

Short Answer

Expert verified

The mass of the rod is 5,134.62 grams

Step by step solution

01

Given Information 

The mass of a cylindrical rod with a radius of 3 centimeters and a length of 20 centimeters . the density of the rod x centimeters isÒÏ(x)=8.93−0.015x

02

Formula 

Volume of cylinder is Ï€°ù2h

where 'r' is the radius and h is the height of the cylinder

Each slice is of radius 3 and width ∆x

So, the volume becomes

Ï€°ù2hÏ€(3)2∆x9π∆x

03

Density 

Density of entire slice is

ÒÏ(xi)=8.93−0.015xiÒÏ=MV8.93−0.015xi=M9π∆xM=8.93−0.015xi9π∆x

04

Sum 

approximate mass is given by sum

∑8.93−0.015xi9π∆xiTogettotalmass,accumulatethemassfromx=0to20Mass=∫0208.93−0.015x9Ï€»å³æ=9π∫0208.93−0.015xdx=9Ï€8.93x-0.015x22020=9Ï€8.93(20)-0.015(20)22=5134.62grams

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