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Use antidifferentiation and/or separation of variables to solve each of the initial-value problems in Exercises 29–52

dydx=2xy2,y(0)=4

Short Answer

Expert verified

The solution of the differential equation and obtain the solution of the initial-value problem dydx=2xy3asyx=3x2+643

Step by step solution

01

Step 1. Given information

The given initial value problemdydx=2xy2,y(0)=4................(1)

02

Step 2. Use antidifferentiation and/or separation of variables to solve each of the initial-value 

Note that the differential equation involved in (1) is of the formdydx=p(x)p(y)in whichp(x)=2x, andq(y)=1y2. So, the differential equation can be solved by applying variable separable method. Thus, the solution of the differential equation involved in the initial- value problem is given by
∫y2dy=∫2xdx13y3=x2+C1y3=3x2+C(3C1=C)y=3x2+C3
Now, use the given initial condition y(0)=4, that is take x=0,y=4 in the above result and evaluate the constant C.

4=C3C=64

Substitute this value of the constant C in the solution of the differential equation and obtain the solution of the initial-value problemdydx=2xy3asyx=3x2+643

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