Chapter 3: Problem 32
Construct \(g(x)\) to be "odd around \(x=\pi . "\)
Short Answer
Expert verified
The function is \( g(x) = x - \pi \), making it odd around \( x = \pi \).
Step by step solution
01
Understanding the Odd Function Definition
A function is considered odd if it satisfies the condition \( f(-x) = -f(x) \) for all \( x \). In this case, however, we are asked to construct a function that is 'odd' around a specific point, \( x = \pi \). This means that the function shifted by \( \pi \), i.e., \( f(x + \pi) \), should be odd around the origin.
02
Shift the Function
To create a function that is odd around \( x = \pi \), first consider shifting the function so that it centers around 0. Define \( g(x) = h(x - \pi) \) where \( h(x) \) is an odd function.
03
Choose an Odd Function
As a base, you can use a simple odd function such as \( h(x) = x \). This is a classic odd function since \( h(-x) = -h(x) \).
04
Construct the Final Function
Now apply the shift to construct \( g(x) \):\[ g(x) = (x - \pi) \]This function will be 'odd around \( x = \pi \)' because if you substitute \( x' = x - \pi \), the function becomes \( g(x') = x' \), which satisfies the odd function property \( g(-x') = -g(x') \).
05
Verify Oddness Around \( x=\pi \)
Check that \( g(\pi + t) = -(g(\pi - t)) \). Calculate:For \( g(\pi + t) = (\pi + t - \pi) = t \)For \( g(\pi - t) = (\pi - t - \pi) = -t \)This confirms that \( g(\pi + t) = -g(\pi - t) \), proving that the function is odd around \( x = \pi \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Transformation
Function transformation is a powerful tool in mathematics that allows us to shift, stretch, shrink, or reflect functions in a variety of ways. Think of function transformations as ways to manipulate a function to create a new one. This involves altering the graph's position or shape. Specifically, transformations include:
- **Shifts:** Moving the graph horizontally or vertically.
- **Stretches and Shrinks:** Scaling the graph of the function up or down.
- **Reflections:** Flipping the graph over a line, typically the x-axis or y-axis.
Function Symmetry
Function symmetry refers to a situation where a function exhibits a consistent pattern when reflected or rotated. In mathematics, symmetry can be:
Such a transformation requires taking a known odd function, like \(h(x) = x\), and applying it to the adjusted domain of \(x - \pi\). The transformation ensures that the new function \(g(x) = x - \pi\) retains odd symmetry. Confirming its odd nature involves verifying that swapping a point across \(x = \pi\) results in a negative of the original function value.
- **Even:** A function is even if it's symmetrical about the y-axis, represented by the equation \(f(x) = f(-x)\).
- **Odd:** This is when a function is symmetric about the origin, meaning \(f(-x) = -f(x)\).
Such a transformation requires taking a known odd function, like \(h(x) = x\), and applying it to the adjusted domain of \(x - \pi\). The transformation ensures that the new function \(g(x) = x - \pi\) retains odd symmetry. Confirming its odd nature involves verifying that swapping a point across \(x = \pi\) results in a negative of the original function value.
Coordinate Shift
A coordinate shift, sometimes referred to as translation, is one of the simplest types of function transformations that changes the position of function on a graph. This shift is essential to constructing functions like \(g(x)\) that are odd around a specific point rather than the typical origin.
In our exercise, the coordinate shift is seen through the term \(x - \pi\). Here, \(\pi\) serves as a kind of 'pivot point'. By "shifting" the function such that the central point becomes \(x = \pi\), we effectively moved the traditional origin of symmetry without altering the shape of the function.
Think of this as taking the entire function graph and moving it on the x-axis. This modification alters which point on the x-axis serves as the point of reflection or symmetry. It allows us to explore and construct different symmetrical properties by designating a new focus point, providing flexibility in function design, particularly useful in mathematical modeling and problem-solving.
In our exercise, the coordinate shift is seen through the term \(x - \pi\). Here, \(\pi\) serves as a kind of 'pivot point'. By "shifting" the function such that the central point becomes \(x = \pi\), we effectively moved the traditional origin of symmetry without altering the shape of the function.
Think of this as taking the entire function graph and moving it on the x-axis. This modification alters which point on the x-axis serves as the point of reflection or symmetry. It allows us to explore and construct different symmetrical properties by designating a new focus point, providing flexibility in function design, particularly useful in mathematical modeling and problem-solving.