Chapter 3: Problem 1
The vertex of \(y=a x^{2}+b x+c\) is at \(x=-b / 2 a\). What is special about this \(x\) ? Show that it gives \(y=c-\left(b^{2} / 4 a\right)\).
Short Answer
Expert verified
The vertex \( x \) gives the minimum/maximum \( y = c - \frac{b^2}{4a} \) of the parabola.
Step by step solution
01
Determine the Expression for Vertex
The vertex of a parabola given by the function \( y = ax^2 + bx + c \) can be determined by the formula \( x = \frac{-b}{2a} \). This \( x \) value represents the point where the parabola reaches its minimum (if \( a > 0 \)) or maximum (if \( a < 0 \)). It is the point of symmetry for the graph of the parabola.
02
Substitute the x-value into the Original Equation
Substitute \( x = \frac{-b}{2a} \) into the quadratic function \( y = ax^2 + bx + c \) to find the corresponding \( y \)-value. Replace every instance of \( x \) with \( \frac{-b}{2a} \).
03
Simplify the Expression
Substitute \( x = \frac{-b}{2a} \) in \( y = ax^2 + bx + c \) and simplify:\[ y = a \left( \frac{-b}{2a} \right)^2 + b \left( \frac{-b}{2a} \right) + c \]Simplify inside the parentheses:\[ y = a \left( \frac{b^2}{4a^2} \right) - \frac{b^2}{2a} + c \]Combine the terms:\[ y = \frac{ab^2}{4a^2} - \frac{b^2}{2a} + c \]Which simplifies to:\[ y = \frac{b^2}{4a} - \frac{2b^2}{4a} + c \]\[ y = c - \frac{b^2}{4a} \].
04
Confirm the Simplification
After simplifying, we have shown that at the vertex, the \( y \)-value is \( y = c - \frac{b^2}{4a} \). This result confirms that the value of \( y \) at \( x = \frac{-b}{2a} \) is special because it reflects the minimum or maximum value of the parabola, depending on the sign of \( a \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Function
A quadratic function is a type of polynomial function that is characterized by its highest degree being 2. It is generally expressed in the form \( y = ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants, and \( a eq 0 \). This equation forms the graph of a parabola when plotted on a coordinate plane.
- \( a \): Determines the width and direction of the parabola. If it's positive, the parabola opens upwards, indicating a minimum point. If negative, it opens downwards, indicating a maximum point.
- \( b \): Affects the position of the vertex horizontally. It impacts the symmetry axis of the parabola.
- \( c \): Represents the y-intercept of the parabola. It's where the graph intersects the y-axis.
Symmetry of a Parabola
The symmetry of a parabola is a fascinating aspect that makes it a neat geometric figure. A parabola is symmetric concerning its vertex, meaning you can draw a line through the vertex called the axis of symmetry, and both halves of the parabola will mirror each other. The equation of this line is given by \( x = \frac{-b}{2a} \). Every parabola has exactly one axis of symmetry, and understanding this helps in predicting the parabola's precise shape and plotting it more efficiently. Notably, locating the axis of symmetry:
- Helps in determining the vertex, as it passes through the vertex point.
- Ensures that the values on one side of the parabola are mirrored on the other side.
- Assists in graph balancing, especially when calculating symmetric points for plots.
Maximum and Minimum of a Parabola
Understanding the maximum and minimum values of a parabola is essential when analyzing a quadratic function. These points indicate the highest or lowest point on the curve, which can be of great significance depending on the application.
- For a parabola that opens upwards \((a > 0)\), the vertex represents the minimum point on the parabola. Thus, the y-coordinate of the vertex is the smallest value that the function can attain.
- Conversely, for a parabola that opens downwards \((a < 0)\), the vertex signifies the maximum point, where the y-coordinate is the largest value.