Chapter 2: Problem 27
Find solutions to \(d y / d x=\sin 3 x\) and \(d y / d x=\cos 3 x\).
Short Answer
Expert verified
Solutions: \(y = -\frac{1}{3}\cos 3x + C\) and \(y = \frac{1}{3}\sin 3x + C\).
Step by step solution
01
Identify Differential Equation Type for Equation 1
The first equation given is a separable first-order ordinary differential equation: \(\frac{dy}{dx} = \sin 3x\). This implies that the solution is an antiderivative problem.
02
Integrate Equation 1
Integrate \(\sin 3x\) with respect to \(x\) to find \(y\). The antiderivative of \(\sin 3x\) is \(-\frac{1}{3}\cos 3x\) since the derivative of \(-\cos 3x\) is \(3\sin 3x\), thus when divided by 3, it matches our integrand. The general solution is \(y = -\frac{1}{3}\cos 3x + C\) where \(C\) is the constant of integration.
03
Identify Differential Equation Type for Equation 2
The second equation is also a separable first-order ordinary differential equation: \(\frac{dy}{dx} = \cos 3x\), indicating another antiderivative problem.
04
Integrate Equation 2
Integrate \(\cos 3x\) with respect to \(x\) to find \(y\). The antiderivative of \(\cos 3x\) is \(\frac{1}{3}\sin 3x\) since the derivative of \(\sin 3x\) is \(3\cos 3x\), thus when divided by 3, it matches our integrand. The general solution is \(y = \frac{1}{3}\sin 3x + C\) where \(C\) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Antiderivatives
Understanding antiderivatives is a crucial step in solving differential equations like the ones given in the exercise. In simple terms, an antiderivative is the reverse process of differentiation. It involves finding a function whose derivative is the original function you started with. In the context of this exercise:
- The antiderivative of \( rac{dy}{dx} = ext{sin}3x \) is \( y = -\frac{1}{3} ext{cos}3x + C \).
- Similarly, for the equation \( rac{dy}{dx} = ext{cos}3x \), the antiderivative is \( y = \frac{1}{3} ext{sin}3x + C \).
- The derivative of \( ext{sin}x \) is \( ext{cos}x \).
- The derivative of \( ext{cos}x \) is \(- ext{sin}x \).
First-Order Differential Equations
First-order differential equations are those where the highest derivative, or rate of change, is the first derivative. They're crucial in modeling a wide array of real-world phenomena, from physical systems to population dynamics. In our context, the differential equations \( \frac{dy}{dx} = \sin 3x \) and \( \frac{dy}{dx} = \cos 3x \) are prime examples of such equations. These equations are classified as **separable**, meaning they can be rewritten to allow the variables \( x \) and \( y \) to be on different sides of the equation. This property simplifies integration since each variable can be independently integrated. Here's what makes these equations distinct:
- **Separable:** the ability to express the equation such that one side contains only derivatives related to \( y \), and the other side involves only \( x \).
- **Ordinary:** only involves one independent variable, in this case, \( x \).
- **Straightforward to solve:** through integration techniques when separable, the solution is often reachable with basic calculus knowledge.
Constant of Integration
When solving differential equations, each antiderivative obtained will have a constant added to it - the constant of integration, denoted as \( C \). This constant represents the family of all possible solutions that differ by a constant value, indicating the dependency of the solution on initial conditions or boundary conditions, if known. Consider the two solutions from the exercise:
- \( y = -\frac{1}{3}\text{cos} 3x + C \)
- \( y = \frac{1}{3}\text{sin} 3x + C \)