Chapter 15: Problem 4
Compute the flux \(\iint \mathbf{F} \cdot \mathbf{n} d S\) by the Divergence Theorem. \(\mathbf{F}=x^{2} \mathbf{i}+8 \mathbf{y}^{2} \mathbf{j}+\boldsymbol{z}^{2} \mathbf{k}, \quad V ;\) unit cube.
Short Answer
Expert verified
The flux is 10.
Step by step solution
01
Understand the Divergence Theorem
The Divergence Theorem relates the flux of a vector field through a closed surface to the divergence of the field inside the volume. Mathematically, it states that \( \iint_S \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_V abla \cdot \mathbf{F} \, dV \), where \( S \) is the boundary of volume \( V \) and \( \mathbf{n} \) is the unit normal to the surface.
02
Compute the Divergence
The divergence of a vector field \( \mathbf{F} = P \mathbf{i} + Q \mathbf{j} + R \mathbf{k} \) is given by \( abla \cdot \mathbf{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \). For \( \mathbf{F} = x^2 \mathbf{i} + 8y^2 \mathbf{j} + z^2 \mathbf{k} \), the divergence is: \( abla \cdot \mathbf{F} = \frac{\partial}{\partial x}(x^2) + \frac{\partial}{\partial y}(8y^2) + \frac{\partial}{\partial z}(z^2) = 2x + 16y + 2z \).
03
Set Up the Integral Over the Volume
The unit cube has corners at \( (0,0,0) \) to \( (1,1,1) \). We need to integrate \( abla \cdot \mathbf{F} = 2x + 16y + 2z \) over this volume: \[ \iiint_V (2x + 16y + 2z) \, dx \, dy \, dz \].
04
Integrate with Respect to x
Perform the integral with respect to \( x \) first: \[ \int_0^1 (2x + 16y + 2z) \, dx = \left[ x^2 + 16xy + 2xz \right]_0^1 = 1 + 16y + 2z \].
05
Integrate with Respect to y
Now, integrate the resulting expression with respect to \( y \): \[ \int_0^1 (1 + 16y + 2z) \, dy = \left[ y + 8y^2 + 2yz \right]_0^1 = 1 + 8 + 2z = 9 + 2z \].
06
Integrate with Respect to z
Perform the final integration with respect to \( z \): \[ \int_0^1 (9 + 2z) \, dz = \left[ 9z + z^2 \right]_0^1 = 9 + 1 = 10 \].
07
Conclusion
The flux of \( \mathbf{F} \) through the surface of the unit cube using the Divergence Theorem is \( 10 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Flux Calculation
Flux refers to how much of a vector field passes through a surface. Imagine you have water flowing through a net. The amount of water passing through can be thought of as flux. For vector fields, this is measured by the surface integral \( \iint_S \mathbf{F} \cdot \mathbf{n} \, dS \), where \( \mathbf{F} \) is the vector field and \( \mathbf{n} \) is a vector normal to the surface. This gives a precise way to calculate how much of the "field" is passing through a boundary.
- Calculating flux across closed surfaces can be simplified using the Divergence Theorem.
- This theorem converts a difficult surface integral into an easier volume integral.
Vector Fields
A vector field assigns a vector to each point in space. These vectors can represent various quantities like velocity of a fluid, gravitational fields, or even magnetic and electric fields. For example, the vector field \( \mathbf{F} = x^2 \mathbf{i} + 8y^2 \mathbf{j} + z^2 \mathbf{k} \) describes a field where each vector depends on its position in three-dimensional space.
- In this field, the 'i' component increases with \( x^2 \), meaning stronger influence as x increases.
- The 'j' component, linked to \( 8y^2 \), grows faster due to the coefficient 8, making changes in y more significant.
- The 'k' component varies with \( z^2 \), affecting the field vertically.
Volume Integration
Volume integration involves integrating a function over a three-dimensional region. In the context of the Divergence Theorem, it allows us to transform a surface integral into a volume integral. For our vector field, we compute the divergence \( abla \cdot \mathbf{F} \), which measures the rate of change or "spread" of the field within the volume.
- The divergence in our problem is given by \( abla \cdot \mathbf{F} = 2x + 16y + 2z \).
- We integrate this over the volume of the unit cube \( V \), with limits from \( (0,0,0) \) to \( (1,1,1) \).
- The integration is done across each dimension: \( x \), \( y \), and \( z \).
Surface Integrals
Surface integrals allow us to calculate the flux across a surface by integrating over that surface in three-dimensional space. More formally, a surface integral \( \iint_S \mathbf{F} \cdot \mathbf{n} \, dS \) involves vectors and a surface area, considering how the vector field intersects each point on that surface.
- This type of integral can be intuitively understood as summing up the flow across a curved or flat boundary.
- Surface integrals take into account both the field's intensity and its direction relative to the surface.
- The direction of the normal vector \( \mathbf{n} \) is crucial as it defines what 'outward' flux means.