Chapter 13: Problem 41
The matrix in Newton's method is the Jacobian: $$J=\left[\begin{array}{ll}\partial g / \partial x & \partial g / \partial y \\\ \partial h / \partial x & \partial h / \partial y\end{array}\right] \quad \text { and } \quad J\left[\begin{array}{l}\Delta x \\ \Delta y\end{array}\right]=\left[\begin{array}{l}-g_{n} \\\\-h_{n}\end{array}\right]$$ Find \(J\) and \(\Delta x\) and \(\Delta y\) for \(g=e^{x}-1, h=e^{y}+x\).
Short Answer
Step by step solution
Calculate the Partial Derivatives for g
Calculate the Partial Derivatives for h
Form the Jacobian Matrix J
Set Up the System of Linear Equations
Solve for \(\Delta x\)
Solve for \(\Delta y\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Newton's Method
Here is how it generally works:
- Initially, an approximation is made to the root or solution of a function.
- Then, the method uses derivatives to refine this approximation.
- Gradually, the solution converges to a more accurate estimate.
Partial Derivatives
For example, if a function is given by:
- \( g(x, y) = e^x - 1 \), then:
- \( \frac{\partial g}{\partial x} = e^x \) - indicating the rate of change of \( g \) with respect to \( x \).
- \( \frac{\partial g}{\partial y} = 0 \) - showing no change with respect to \( y \) since \( y \) is not present in the expression.
- \( h(x, y) = e^y + x \), then:
- \( \frac{\partial h}{\partial x} = 1 \) - the rate of change of \( h \) with respect to \( x \).
- \( \frac{\partial h}{\partial y} = e^y \) - the change concerning \( y \).
Linear Equations
- Each equation in the system can be represented with a matrix equation: \( A\mathbf{x} = \mathbf{b} \), where \( A \) is a matrix, \( \mathbf{x} \) is a vector of variables, and \( \mathbf{b} \) is a vector of constants.
- For instance, the system given by our Jacobian analysis can be structured as:
- \[ \begin{bmatrix} e^x & 0 \ 1 & e^y \end{bmatrix} \begin{bmatrix} \Delta x \ \Delta y \end{bmatrix} = \begin{bmatrix} -g_n \ -h_n \end{bmatrix} \]
- Solving this set of linear equations requires using techniques such as substitution or matrix operations.
Functions
- A function like \( g(x, y) = e^x - 1 \) is defined for each \( x \) and \( y \) within a domain and outputs results based on these inputs.
- Similarly, \( h(x, y) = e^y + x \) combines the effect of both variables simultaneously, showing the collaborative nature of functions in multivariable problems.
- Functions help in defining systems of equations that can later be analyzed or solved using tools such as derivatives and matrices.
Matrix Algebra
- In our exercise, the Jacobian matrix \( J \) is formed using partial derivatives to show small changes in functions relative to their input variables.
- By setting up matrices such as \[ \begin{bmatrix} e^x & 0 \ 1 & e^y \end{bmatrix} \], we can model complex systems in a manageable form.
- The Matrix Algebra involves operations like addition, subtraction, and multiplication, as well as the inversion of matrices, which are crucial for finding the solution to sets of linear equations.