Chapter 11: Problem 42
The vectors \(A, B, C\) form a triangle \(i f A+B+C=0\). The triangle inequality \(|\mathbf{A}+\mathbf{B}| \leqslant|\mathbf{A}|+|\mathbf{B}|\) says that any one side length is less than _____ The proof comes from Schwarz: \(\begin{aligned}|\mathbf{A}+\mathbf{B}|^{2} &=\mathbf{A} \cdot \mathbf{A}+2 \mathbf{A} \cdot \mathbf{B}+\mathbf{B} \cdot \mathbf{B} \\ & \leqslant|\mathbf{A}|^{2}+&+|\mathbf{B}|^{2}=(|\mathbf{A}|+|\mathbf{B}|)^{2} . \end{aligned}\)
Short Answer
Step by step solution
Understand Triangle Condition
Analyze the Triangle Inequality
Apply Schwarz's Inequality
Simplify the Inequality
Conclude the Proof
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Key Concepts
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