Chapter 10: Problem 2
Behind every decima! \(s=a b c \ldots\) is a convergent series \(a / 10+b / 100+\) _______\(\ldots \ldots .\) By a comparison test prove convergence.
Short Answer
Expert verified
The series converges by the comparison test with the geometric series \( \sum \frac{1}{10^n} \).
Step by step solution
01
Understand the Series
We have a decimal number expressed as a series: \( s = a.bcd\ldots \). This series can be expanded as \( \frac{a}{10} + \frac{b}{100} + \frac{c}{1000} + \ldots \) where \(a, b, c, \ldots\) are digits ranging from 0 to 9.
02
Write the Series in Mathematical Form
The series can be written in general form as \( \sum_{n=1}^{\infty} \frac{d_n}{10^n} \), where each \( d_n \) is a digit from 0 to 9. This is an infinite series representing the decimal expansion.
03
Identify a Comparison Series
To prove convergence, we need to compare this series with a known convergent series. Consider the geometric series \( \sum_{n=1}^{\infty} \frac{1}{10^n} \), which is known to converge.
04
Apply the Comparison Test
For each term in the given series \( \frac{d_n}{10^n} \), it is clear that \( 0 \leq \frac{d_n}{10^n} \leq \frac{9}{10^n} \). Since \( \sum_{n=1}^{\infty} \frac{9}{10^n} = 9 \times \sum_{n=1}^{\infty} \frac{1}{10^n} \) is a convergent geometric series with sum \( \frac{9}{9} = 1 \), by the comparison test, our series also converges.
05
Conclusion
By the comparison test, since every term in the series \( \frac{d_n}{10^n} \) is bounded above by the corresponding term of the convergent geometric series \( \frac{9}{10^n} \), the original decimal series \( \sum_{n=1}^{\infty} \frac{d_n}{10^n} \) converges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Decimal Expansion
Decimal expansion refers to representing numbers as a sum of fractions. These fractions have powers of ten in the denominator. For example, the decimal number 0.abc... means each digit holds a value based on its position. Hence, it becomes:
- \( a/10 \) for the first digit after the decimal point,
- \( b/100 \) for the second digit,
- \( c/1000 \) for the third digit, and so forth.
Comparison Test
The comparison test is a technique to determine if a series is convergent. It relies on comparing a series you are investigating with a known one. If the series in question has terms that are always smaller than those of a known convergent series, it too converges. Here's how it works:
- Identify the series you wish to analyze. For decimal expansions, it's \( \sum_{n=1}^{\infty} \frac{d_n}{10^n} \).
- Select a known convergent series, like the simple geometric series \( \sum_{n=1}^{\infty} \frac{1}{10^n} \).
- Show that each term in your series is less than or equal to the corresponding term in the known series.
- If the series of larger terms converges, then by the Comparison Test, your original series also converges.
Geometric Series
A geometric series is a series of numbers where each term is found by multiplying the previous one by a fixed, non-zero number called the common ratio. The classic form of a geometric series is:
- \( a, ar, ar^2, ar^3, \ldots \)