Chapter 6: Problem 103
Find the derivative of: \(g(x)=\left[x^{3}\right] /\left[3 \sqrt{ \left.\left(3 x^{2}-1\right)\right]}\right.\)
Short Answer
Expert verified
The derivative of \(g(x) = \frac{x^3}{3(3x^2 - 1)^{1/2}}\) is: \(g'(x) = \frac{x^2(2x^2 - 1)}{(3x^2 - 1)^{3/2}}\).
Step by step solution
01
Rewrite the function with rational exponents
Rewrite the function g(x) with rational exponents instead of the square root: \( g(x) = \frac{x^3}{3(3x^2 - 1)^{1/2}} \)
02
Apply the Quotient Rule
Use the quotient rule to differentiate g(x) with respect to x. The quotient rule states that if we have a function in the form of \(\frac{u(x)}{v(x)}\), then its derivative with respect to x is \(\frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^2}\). In our case, we have \(u(x) = x^3\) and \(v(x) = 3(3x^2 - 1)^{1/2}\).
03
Find the derivatives u'(x) and v'(x)
We now need to find the derivatives of u(x) and v(x) with respect to x:
- For u(x), the derivative is straightforward: \(u'(x) = 3x^2\).
- For v(x), we need to use the chain rule since we have a composite function: \(v(x) = 3(3x^2 - 1)^{1/2}\). The chain rule states that if we have a function h(x) in the form of: \(h(x) = f(g(x))\), then its derivative with respect to x is \(h'(x) = f'(g(x)) \cdot g'(x)\). Applying this, we get:
\(v'(x) = \frac{1}{2}(3x^2 - 1)^{-1/2} \cdot 6x\)
04
Plug u'(x) and v'(x) back into the Quotient Rule formula
Now plug these derivatives back into the quotient rule formula: \[\frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^2} = \frac{3x^2\cdot3(3x^2 - 1)^{1/2} - x^3\cdot\frac{1}{2}(3x^2 - 1)^{-1/2}\cdot6x}{[3(3x^2 - 1)^{1/2}]^2}\]
05
Simplify the result
Now simplify the expression for the derivative:
\[\frac{9x^2(3x^2 - 1)^{1/2} -3x^4(3x^2 - 1)^{-1/2}}{9(3x^2 - 1)}\]
Factor out a \(3x^2(3x^2 - 1)^{-1/2}\) from the numerator:
\[\frac{3x^2(3x^2 - 1)^{-1/2}(3(3x^2 - 1) - x^2)}{9(3x^2 - 1)}\]
Reduce the expression to get the final simplified form:
\[g'(x) = \frac{x^2(2x^2 - 1)}{(3x^2 - 1)^{3/2}}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quotient Rule
When differentiating a function that is the quotient of two other functions, the Quotient Rule is an essential tool. It is used when we have a function in the form \( \frac{u(x)}{v(x)} \), where both \( u \) and \( v \) are themselves differentiable functions of \( x \). The derivative of the quotient is given by the formula \( \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^2} \).
To apply this rule effectively, you must:
To apply this rule effectively, you must:
- Identify the numerator function \( u(x) \) and the denominator function \( v(x) \) in your quotient.
- Find the derivatives of these functions separately, denoted as \( u'(x) \) and \( v'(x) \).
- Substitute \( u'(x) \) and \( v'(x) \) into the Quotient Rule formula.
- Simplify the resulting expression wherever possible.
Chain Rule
The Chain Rule comes into play when we need to find the derivative of a composite function—a function of a function. The Chain Rule states that if you have a function \( h(x) \) that can be written as \( f(g(x)) \) (where \( f \) and \( g \) are both functions of \( x \) that have derivatives), then the derivative of \( h \) with respect to \( x \) is \( h'(x) = f'(g(x)) \cdot g'(x) \).
To use the Chain Rule, follow these steps:
To use the Chain Rule, follow these steps:
- Identify the outer function \( f \) and the inner function \( g \) in your composite function.
- Compute the derivative of the outer function \( f '\) with respect to its argument (which is the inner function \( g \) in our case).
- Find the derivative of the inner function \( g'(x) \) with respect to \( x \).
- Multiply these derivatives to get the derivative of the composite function \( h'(x) \).
Rational Exponents
Functions containing rational exponents, like \( (3x^2 - 1)^{1/2} \) in our exercise, are another form of expressing roots. The rational exponent \( 1/2 \) represents a square root, while \( 1/3 \) would be a cube root, and so on. Rational exponents follow the same rules as integral exponents, making them convenient for differentiating.
Here's how to work with rational exponents:
Here's how to work with rational exponents:
- Convert roots into expressions with rational exponents to simplify the differentiation process, as they are easier to handle using the regular rules of differentiation.
- Remember that for any function \( x^n \), where \( n \) is a rational number, the derivative is \( nx^{n-1} \).
- In the case of functions with rational exponents, the Chain Rule is often applied if the base of the power function is itself a function of \( x \).