Chapter 5: Problem 69
Find the derivative of \(\mathrm{f}(\mathrm{x})=[2 /(3 \mathrm{x}+1)]\), using the \(\Delta\) -method.
Short Answer
Expert verified
The derivative of the function \(f(x) = \frac{2}{3x+1}\) using the delta method is \(f'(x) = \frac{-6}{(3x+1)^2}\).
Step by step solution
01
Write down the difference quotient formula
The difference quotient formula is given by:
\(\frac{f(x+\Delta x)-f(x)}{\Delta x}\)
We will use this formula to derive the derivative of the function \(f(x) = \frac{2}{3x+1}\) using the delta method.
02
Substitute the function into the difference quotient formula
Replace the function f(x) and f(x + Δx) in the difference quotient formula:
\(\frac{\frac{2}{3(x+\Delta x)+1} - \frac{2}{3x+1}}{\Delta x}\)
03
Simplify the difference quotient
To simplify the difference quotient expression, find a common denominator for the fractions in the numerator by multiplying the denominators:
\(\frac{(2(3x+1) - 2(3(x+\Delta x)+1))}{(3x+1)(3(x+\Delta x)+1)\Delta x}\)
Now, simplify the numerator and expand the expression:
\(\frac{(6x+2 - 6(x+\Delta x)-2)}{(3x+1)(3x+3\Delta x+1)\Delta x}\)
\(\frac{-6\Delta x}{(3x+1)(3x+3\Delta x+1)\Delta x}\)
04
Cancel out the common terms
We cancel out the common term \(\Delta x\) from the numerator and denominator:
\(\frac{-6}{(3x+1)(3x+3\Delta x+1)}\)
05
Take the limit as Δx approaches 0
Now we take the limit of the difference quotient as Δx approaches 0:
\(\lim_{\Delta x \to 0}\frac{-6}{(3x+1)(3x+3\Delta x+1)}\)
When \(\Delta x\) approaches 0, the expression in the limit becomes:
\(\frac{-6}{(3x+1)(3x+1)}\)
06
Write down the final answer
The derivative of the function \(f(x) = \frac{2}{3x+1}\) using the delta method is:
\(f'(x) = \frac{-6}{(3x+1)^2}\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference Quotient
The difference quotient is a crucial element in calculus as it helps to find the derivative of a function. Essentially, the difference quotient is a formula for the average rate of change of the function over a small interval. It is expressed as:
- \( \frac{f(x+\Delta x)-f(x)}{\Delta x} \)
Delta Method
The delta method is a specific application of the difference quotient tailored to find derivatives. When a problem asks to "use the delta method," it usually involves:
- Substituting \( f(x) \) and \( f(x+\Delta x) \) directly into the difference quotient formula.
- Simplifying the resulting algebraic expression.
- Applying limits to the expression as \( \Delta x \) approaches zero.
Limits
In calculus, limits are fundamental and pivotal to the concept of derivatives. A limit seeks to find the value a function approaches as the input gets exceedingly close to a certain point. When using the delta method, you often encounter limits in the step where \( \Delta x \to 0 \). Here's how limits work in this context:
- You simplify the difference quotient expression.
- To find the derivative, take the limit of this quotient as \( \Delta x \) becomes infinitesimally small (approaches zero).
Rational Functions
Rational functions, which are the ratio of two polynomials, are common in calculus, like the function \( f(x) = \frac{2}{3x+1} \). Working with rational functions requires familiarity with their algebraic behavior, especially when finding derivatives. Here are some key points to consider:
- They often involve fractions, which require finding common denominators.
- Derivatives of rational functions frequently involve simplification of complex terms.
- Limits play a critical role in controlling indeterminate forms that might arise when dividing by small quantities, like \( \Delta x \).