/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1116 Find a first-order differential ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find a first-order differential equation satisfied by all circles with center at the origin.

Short Answer

Expert verified
The first-order differential equation satisfied by all circles with center at the origin is: \( \frac{dy}{dx} = -\frac{x}{y} \)

Step by step solution

01

General equation of a circle centered at the origin

The general equation of a circle with radius R and centered at the origin (0,0) is given by: \(x^2 + y^2 = R^2\)
02

Differentiating with respect to x

Now, we will implicitly differentiate the equation with respect to x, since we are looking for a differential equation that involves the derivative: \(\frac{d}{dx}(x^2) + \frac{d}{dx}(y^2) = \frac{d}{dx}(R^2)\) Applying the power rule to differentiate, we get: \(2x + 2y \frac{dy}{dx} = 0\)
03

Simplify the equation

We can simplify the equation by dividing both sides by 2: \(x + y \frac{dy}{dx} = 0\)
04

Rearrange the equation

We can rearrange the equation to make \(\frac{dy}{dx}\) the subject, getting the final equation as: \(\frac{dy}{dx} = -\frac{x}{y}\) Thus, the first-order differential equation satisfied by all circles with center at the origin is: \(\frac{dy}{dx} = -\frac{x}{y}\)

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