Chapter 4: Problem 58
Investigate continuity of: $$ F(x)=\mid \begin{array}{ll} x-3 \mid & \text { if } x \neq 3 \\ 2 & \text { if } x=3 \end{array} $$
Short Answer
Expert verified
The function F(x) is not continuous at x=3, because while the left-hand limit and right-hand limit both exist and are equal to 0, they are not equal to the value of F(3) = 2.
Step by step solution
01
Determine the limits of F(x) from the left and right of x=3.
To find the left-hand limit, we will evaluate the function F(x) as x approaches 3 from the left. Since F(x) is defined as |x-3| for x ≠3, we can calculate the left-hand limit using the absolute value function and consider x to be slightly less than 3, as such: \(\lim_{x \to 3^-} |x-3|\).
To find the right-hand limit, we will evaluate the function F(x) as x approaches 3 from the right. We will again use the absolute value function but with x to be slightly greater than 3, as such: \(\lim_{x \to 3^+} |x-3|\).
02
Evaluate the left-hand limit.
To evaluate the left-hand limit, \(\lim_{x \to 3^-} |x-3|\), think about what happens to \(|x-3|\) as x gets closer to 3 from the left (x values smaller than 3). When x is less than 3, \(x-3\) will be negative, and so the absolute value function will make the result positive:
\(|x-3| = -(x-3)\)
Therefore, the left-hand limit will be:
\(\lim_{x \to 3^-} |x-3| = \lim_{x \to 3^-} -(x-3)\)
As x approaches 3 from the left, the expression (x-3) approaches 0, and so the left-hand limit is 0.
03
Evaluate the right-hand limit.
To evaluate the right-hand limit, \(\lim_{x \to 3^+} |x-3|\), think about what happens to \(|x-3|\) as x gets closer to 3 from the right (x values greater than 3). When x is greater than 3, \(x-3\) will be positive, and so the absolute value function does not affect the result:
\(|x-3| = x-3\)
Therefore, the right-hand limit will be:
\(\lim_{x \to 3^+} |x-3| = \lim_{x \to 3^+} (x-3)\)
As x approaches 3 from the right, the expression (x-3) also approaches 0, and so the right-hand limit is 0.
04
Compare the left-hand limit, right-hand limit, and F(3).
Now, we have the left-hand limit, the right-hand limit, and F(3) as follows:
Left-hand limit: 0
Right-hand limit: 0
F(3): 2
Since the left-hand limit and the right-hand limit are equal (0), the limit of the function F(x) exists at x=3. However, because F(3) = 2 is not equal to the limit (0), F(x) is not continuous at x=3.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Left-Hand Limit
When discussing the concept of a left-hand limit, we refer to the behavior of a function as it approaches a particular point from the left. In this case, the point of interest is 3. For the function \( F(x) = |x-3| \) when \( x eq 3 \), we examine what happens as \( x \) gets closer to 3 from values less than 3.
To find the left-hand limit, consider that if \( x < 3 \), then \( x-3 \) is negative. The absolute value, \( |x-3| \), will negate this negative value to ensure a positive output. Thus, it behaves as \( |x-3| = -(x-3) \).
As x approaches 3 from the left, \( (x-3) \) moves towards 0. Thus, the left-hand limit is:
To find the left-hand limit, consider that if \( x < 3 \), then \( x-3 \) is negative. The absolute value, \( |x-3| \), will negate this negative value to ensure a positive output. Thus, it behaves as \( |x-3| = -(x-3) \).
As x approaches 3 from the left, \( (x-3) \) moves towards 0. Thus, the left-hand limit is:
- \( \lim_{x \to 3^-} |x-3| = 0 \)
Right-Hand Limit
The right-hand limit explores the behavior of the function as it approaches a particular value from the right. For our function, we observe \( F(x) = |x-3| \) when \( x eq 3 \), especially as \( x \) gets close to 3 from values greater than 3.
In this scenario, since \( x > 3 \), \( x-3 \) is positive. The absolute value does not change this, so \( |x-3| = x-3 \). When x nears 3 from the right, this simply approaches 0:
In this scenario, since \( x > 3 \), \( x-3 \) is positive. The absolute value does not change this, so \( |x-3| = x-3 \). When x nears 3 from the right, this simply approaches 0:
- \( \lim_{x \to 3^+} |x-3| = 0 \)
Limit Definition of Continuity
To determine continuity at a point, the limit definition states that the function's value at that point must equal the limit from both sides. In mathematical terms, a function \( F(x) \) is continuous at a point \( x=c \) if:
Because the value of the function at \( x=3 \) (which is 2) does not match the limit (which is 0), \( F(x) \) is not continuous at \( x=3 \). This discrepancy is vital for understanding when functions behave smoothly or have interruptions.
- \( \lim_{x \to c^-} F(x) = \lim_{x \to c^+} F(x) = F(c) \)
Because the value of the function at \( x=3 \) (which is 2) does not match the limit (which is 0), \( F(x) \) is not continuous at \( x=3 \). This discrepancy is vital for understanding when functions behave smoothly or have interruptions.
Piecewise Function
A piecewise function is a function defined by different expressions based on the input's range. In this context, the function \( F(x) \) changes its formula depending on whether \( x=3 \) or not.
- When \( x eq 3 \), \( F(x) = |x-3| \)
- When \( x = 3 \), \( F(x) = 2 \)