/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Patricia wishes to have a rectan... [FREE SOLUTION] | 91Ó°ÊÓ

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Patricia wishes to have a rectangular-shaped garden in her backyard. She has \(80 \mathrm{ft}\) of fencing with which to enclose her garden. Letting \(x\) denote the width of the garden, find a function \(f\) in the variable \(x\) that gives the area of the garden. What is its domain?

Short Answer

Expert verified
The function representing the area of the garden is \(f(x) = (40-x) \times x\), and its domain is \((0, 40)\).

Step by step solution

01

Write the perimeter formula for a rectangle

The perimeter of a rectangle can be given as \(P = 2l + 2w\), where \(P\) is the perimeter, \(l\) is the length of the rectangle, and \(w\) is the width of the rectangle.
02

Write the area formula for a rectangle

The area of a rectangle can be given as \(A =l \times w\), where \(A\) is the area, \(l\) is the length of the rectangle, and \(w\) is the width of the rectangle.
03

Solve the perimeter formula for the length

We are given that the total amount of fencing material Patricia has is 80 ft, which means \(P = 80\). Using the perimeter formula, we can solve for the length variable \(l\) in terms of the width \(w\): \(P = 2l + 2w\) \\ \(80 = 2l + 2w\) \\ Divide both sides by 2: \\ \(40 = l + w\) \\ Now, solve for \(l\): \\ \(l = 40 - w\)
04

Substitute the length expression in the area formula

We now have an expression for the length \(l\) in terms of the width \(w\). Substitute this expression into the area formulaA = l × w: \(A = (40 - w) \times w\)
05

Simplify the area function

Simplify the area function to get the function \(f\) in terms of the width \(x\). Since we are asked for a function \(f(x)\), we will replace \(w\) with \(x\): \(f(x) = (40-x) \times x\)
06

Find the domain of the function

Now, we need to find the domain of the function \(f(x)\). The domain will be the set of possible values for the width \(x\) given that the length and the width must be positive and the total perimeter is 80 ft. We have the length expression as \(l = 40 - x\), and we know that \(l > 0\) and \(x > 0\). This means that the length and width values must fall within the following range: \(0 < x < 40\) So, the domain of the function \(f(x)\) is: \((0, 40)\) To summarize: - The function that represents the area of the garden in terms of its width, \(x\), is given by: \(f(x) = (40-x) \times x\) - The domain of the function \(f(x)\) is \((0, 40)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perimeter of a Rectangle
Understanding the perimeter of a rectangle is essential when working with the dimensions of any rectangular space, such as Patricia's garden. The perimeter is the total distance around the border of the rectangle. In mathematical terms, if we denote the length of the rectangle by l and the width by w, the perimeter formula is expressed as:

\[P = 2l + 2w\]
In this simple formula, multiplying the length and the width by two accounts for the opposite sides of the rectangle, which are congruent in length. Patricia has a total of 80 ft of fencing. This means for her garden, with the length l and the width w, the perimeter must equal to the length of the fence available, hence the equality P = 80 ft. By setting up this equation, we effectively lay the foundation for optimizing the area within.
Area of a Rectangle
In Patricia's situation, finding the area enclosed by the fencing is paramount, since this will determine how much gardening space she will have. The area of a rectangle is found by multiplying the length l by the width w, represented by the formula:

\[A = l \times w\]
When one dimension is a function of the other, as is the case when dealing with a fixed perimeter, we get a relation between the two that can be used to express the area solely in terms of one dimension. This helps in forming a single variable function that can then be analyzed for optimization purposes, a technique necessary for making the best use of the available fencing material.
Function Domain
The domain of a function refers to all the possible input values (in this context, the width x of the rectangle) that will yield a valid output from the function. For Patricia's rectangular garden, the domain is dictated by practical considerations: both the width and the length must be positive numbers, and they must satisfy the total perimeter constraint. Mathematically, the domain of her garden's area function is the set of all width values x that are greater than zero and less than half the perimeter. In interval notation, we write:

\[0 < x < 40\]
This interval defines the set of all permissible widths for the rectangle, which when doubled and added to the corresponding lengths, will not exceed the available 80 ft of fencing. It is a fundamental concept in understanding how constraints affect the optimization of a function in real-world situations.
Quadratic Function
Patricia's area function, once derived, takes the form of a quadratic function, a type of polynomial with a degree of two, typically written as ax2 + bx + c. Here, the function describing the area of her garden is:

\[f(x) = (40 - x)x = -x^2 + 40x\]
This is a quadratic function because the variable x, representing the width, is squared. Quadratic functions are characterized by their unique U-shaped graphs called parabolas, and their optimization—finding their maximum or minimum values—is a frequent goal in real-world applications, such as maximizing the area of a rectangle with given constraints. Understanding the properties of these functions is crucial, as they can model many natural and economic phenomena.

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