/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 A function \(f(x, y)\) that has ... [FREE SOLUTION] | 91Ó°ÊÓ

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A function \(f(x, y)\) that has continuous second derivatives and that satisfies \(f_{x x}+f_{y y}=0\) is called a harmonic function. Harmonic functions have many interesting properties, including the fact that their value at the center of any circle is the average of their values around the circumference of the circle. So if you stretch the edges of a flexible rubber sheet, the shape will be a harmonic function. Find whether each of the following functions is harmonic. \(f(x, y)=x^{2}-y^{2}\)

Short Answer

Expert verified
Yes, the function is harmonic.

Step by step solution

01

Understand the Problem

We need to determine if the function \( f(x, y) = x^{2} - y^{2} \) is harmonic, meaning it satisfies the condition \( f_{xx} + f_{yy} = 0 \), where \( f_{xx} \) and \( f_{yy} \) are the second partial derivatives.
02

Calculate the First Partial Derivatives

To find the second partial derivatives, first calculate the first derivatives. First compute \( f_x \), the partial derivative with respect to \( x \), and \( f_y \), the partial derivative with respect to \( y \).\[ f_x = \frac{\partial}{\partial x} (x^2 - y^2) = 2x \] \[ f_y = \frac{\partial}{\partial y} (x^2 - y^2) = -2y \]
03

Calculate the Second Partial Derivatives

Now calculate the second partial derivatives \( f_{xx} \) and \( f_{yy} \) from the first partial derivatives.\[ f_{xx} = \frac{\partial}{\partial x}(2x) = 2 \] \[ f_{yy} = \frac{\partial}{\partial y}(-2y) = -2 \]
04

Verify the Harmonic Condition

Check if the sum of the second partial derivatives equals zero.\[ f_{xx} + f_{yy} = 2 + (-2) = 0 \] The condition \( f_{xx} + f_{yy} = 0 \) is satisfied.
05

Conclusion

Since \( f_{xx} + f_{yy} = 0 \), the function \( f(x, y) = x^2 - y^2 \) is harmonic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Derivatives
When working with functions of multiple variables, such as a function like \( f(x, y) \), it is often valuable to understand how the function changes as each individual variable changes. This is where partial derivatives come into play. A partial derivative of a function is the derivative with respect to one variable while keeping the other variables constant.

To compute the partial derivatives for the given function \( f(x, y) = x^2 - y^2 \), we start by finding \( f_x \) and \( f_y \). Here, \( f_x \) is the partial derivative with respect to \( x \):
  • \( f_x = \frac{\partial}{\partial x} (x^2 - y^2) = 2x \)
For the variable \( y \), we find \( f_y \):
  • \( f_y = \frac{\partial}{\partial y} (x^2 - y^2) = -2y \)
These partial derivatives describe the rate at which the function \( f \) changes as each variable \( x \) or \( y \) changes, while the other remains constant. Understanding these rates of change is crucial for further calculations of second derivatives.
Second Partial Derivatives
Once you have the first partial derivatives, the next step involves finding the second partial derivatives, which are simply the partial derivatives of the first partial derivatives. These are key in many advanced mathematical analyses, including verifying if a function is harmonic.

For the function \( f(x, y) = x^2 - y^2 \), we use the first derivatives \( f_x = 2x \) and \( f_y = -2y \) to find \( f_{xx} \) and \( f_{yy} \). You're essentially taking the partial derivative of the partial derivative! Here’s how it’s done:
  • \( f_{xx} = \frac{\partial}{\partial x}(2x) = 2 \)
  • \( f_{yy} = \frac{\partial}{\partial y}(-2y) = -2 \)
The second partial derivatives \( f_{xx} \) and \( f_{yy} \) tell us about the curvature of the function in each direction. These derivatives are essential not just for understanding the behavior of the function, but are also used to satisfy the harmonic condition.
Harmonic Condition
The harmonic condition is a fascinating property in mathematics related to functions that resembles the behavior of physical phenomena like heat distribution and electrostatic fields. A function is harmonic if the sum of its second partial derivatives equals zero, specifically \( f_{xx} + f_{yy} = 0 \).

For the function \( f(x, y) = x^2 - y^2 \), we have already calculated the second partial derivatives: \( f_{xx} = 2 \) and \( f_{yy} = -2 \). To check if this function is harmonic, we sum these derivatives:
  • \( f_{xx} + f_{yy} = 2 + (-2) = 0 \)
Since this sum equals zero, the function satisfies the harmonic condition, which confirms that \( f(x, y) = x^2 - y^2 \) is indeed a harmonic function.

Harmonic functions have unique properties, such as the mean value property, which states that the value at a point in a domain can represent an average of values over surrounding areas like circles. This unique behavior is what makes them critical in fields like physics and engineering.

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