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For each function of three variables, find the partials a. \(f_{x r}\) b. \(f_{y}\), and c. \(f_{z}\). \(f=(x y z+1)^{3}\)

Short Answer

Expert verified
(a) \( 6y^2z^2(xyz+1) \), (b) \( 3xz(xyz+1)^2 \), (c) \( 3xy(xyz+1)^2 \)."

Step by step solution

01

Find the first partial derivative with respect to x

To find the first partial derivative of the function with respect to the variable \( x \), we will treat \( y \) and \( z \) as constants. The function is given as \( f = (xyz + 1)^3 \). Applying the chain rule, \[\frac{ \partial f }{ \partial x } = 3 (xyz + 1)^2 \cdot \frac{ \partial }{ \partial x }(xyz + 1) = 3(xyz + 1)^2 \cdot yz.\]Thus, \( f_{x} = 3yz(xyz + 1)^2 \).
02

Find the second mixed partial derivative with respect to xr

Now, we'll differentiate \( f_{x} = 3yz(xyz + 1)^2 \) with respect to \( r \). However, since there is no variable \( r \) in this expression, let's correct this. Assuming you meant to continue referring to \( x \):Differentiating again with respect to \( x \), \[f_{xr} = \frac{ \partial }{ \partial x } (3yz(xyz + 1)^2)\]Apply the product rule and chain rule:\[f_{xr} = 6y^2z^2(xyz + 1).\]
03

Find the first partial derivative with respect to y

Now, we treat \( x \) and \( z \) as constants and differentiate \( f = (xyz + 1)^3 \) with respect to \( y \),\[\frac{ \partial f }{ \partial y } = 3 (xyz + 1)^2 \cdot \frac{ \partial }{ \partial y }(xyz + 1) = 3(xyz + 1)^2 \cdot xz.\]Thus, \( f_{y} = 3xz(xyz + 1)^2 \).
04

Find the first partial derivative with respect to z

Finally, for the partial derivative with respect to \( z \), treat \( x \) and \( y \) as constants:\[\frac{ \partial f }{ \partial z } = 3 (xyz + 1)^2 \cdot \frac{ \partial }{ \partial z }(xyz + 1) = 3(xyz + 1)^2 \cdot xy.\]Therefore, \( f_{z} = 3xy(xyz + 1)^2 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental tool in calculus, especially when dealing with composite functions. In the context of functions of multiple variables, the chain rule helps us differentiate functions that depend on several variables, each of which may be a function of another variable. For example, when differentiating the function \(f = (xyz + 1)^3\), we use the chain rule to handle the composition of the inner function \(xyz + 1\) with the outer function \(u^3\), where \(u = xyz + 1\).
When applying the chain rule to find the partial derivative of \(f\) with respect to \(x\), it breaks down as follows:
  • Differentiating the outer function \((xyz + 1)^3\) with respect to its inner function \(xyz + 1\), we get factor \(3(xyz + 1)^2\).
  • The derivative of the inner function \(xyz + 1\) with respect to \(x\) is \(yz\).
  • Multiplying these results gives us the partial derivative with respect to \(x\): \frac{\partial f}{\partial x} = 3yz(xyz + 1)^2\.
The chain rule simplifies the task of differentiating complex nested functions by unwinding them one layer at a time.
Product Rule
The product rule is essential when you have functions multiplied together, and you need to find the derivative or partial derivative of their product. In calculus, when you have an expression like \(g(x) \, h(x)\), the product rule is stated as:
  • \frac{d}{dx}[g(x) \, h(x)] = g'(x) \, h(x) + g(x) \, h'(x)\.
In the case of partial derivatives and functions of multiple variables, the product rule is applied similarly. For example, to find \(f_{xr}\) with \(f_{x} = 3yz(xyz + 1)^2\), we use the product rule combined with the chain rule:
  • The product is between \(3yz\) and \((xyz + 1)^2\).
  • Applying the product rule: differentiate \(3yz\), keep \((xyz + 1)^2\) unchanged, then add \(3yz\) unchanged and differentiate \((xyz + 1)^2\).
  • This yields \(f_{xr} = 6y^2z^2(xyz + 1)\).
Mastering the product rule helps untangle interactions between products of different functions or variables.
Functions of Multiple Variables
Functions of multiple variables extend the concept of functions from single-variable calculus to cases where there are two or more input variables. These functions are often written as \(f(x, y, z)\) or in similar notations when more variables are involved.
When dealing with these types of functions, each variable can represent a dimension, and the function's output can manifest as a surface or hypersurface in multi-dimensional space. Partial derivatives become particularly important as they allow us to understand how the function changes with respect to each input, holding others constant.
For instance, with \(f = (xyz + 1)^3\), the partial derivatives \(f_x\), \(f_y\), and \(f_z\) tell us how the function \(f\) changes as we slightly alter \(x\), \(y\), or \(z\), respectively, while keeping the other variables constant. This concept is crucial in multiple disciplines such as thermodynamics, economics, and engineering, where systems often depend on several factors.

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