/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 Solve each using Lagrange multip... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each using Lagrange multipliers. (The stated extreme values do exist.) Minimize \(f(x, y, z)=x^{2}+y^{2}+z^{2}\) subject to \(2 x+y-z=12\).

Short Answer

Expert verified
The minimum value is 24 at \((x, y, z) = (4, 2, -2)\).

Step by step solution

01

Define the Function and Constraint

We want to minimize the function \(f(x, y, z) = x^2 + y^2 + z^2\) subject to the constraint \(g(x, y, z) = 2x + y - z = 12\).
02

Setup the Lagrangian Function

The Lagrangian function is given by \( \mathcal{L}(x, y, z, \lambda) = x^2 + y^2 + z^2 + \lambda (2x + y - z - 12) \), where \(\lambda\) is the Lagrange multiplier.
03

Compute the Gradient of the Lagrangian

Calculate the partial derivatives of \( \mathcal{L} \) with respect to \(x\), \(y\), \(z\), and \(\lambda\):\(abla \mathcal{L} = ( 2x + 2\lambda, 2y + \lambda, 2z - \lambda, 2x + y - z - 12).\)
04

Set the Gradient Equal to Zero

Set each partial derivative to zero to obtain the system of equations: \(2x + 2\lambda = 0\), \(2y + \lambda = 0\), \(2z - \lambda = 0\), and the original constraint \(2x + y - z = 12\).
05

Solve the System of Equations

From the equations, solve for \(x\), \(y\), \(z\), and \(\lambda\). From \(2x + 2\lambda = 0\), we have \(\lambda = -x\). From \(2y + \lambda = 0\), \(\lambda = -2y\), hence \(x = 2y\). From \(2z - \lambda = 0\), \(\lambda = 2z\), which gives \(-x = 2z\). Now substitute these into the constraint equation \(2x + y - z = 12\).
06

Substitute Variables and Simplify

Substitute \(x = 2y\) and \(z = -\frac{x}{2}\) into the constraint: \(2(2y) + y + \frac{x}{2} = 12\). Simplify to \(4y + y + y = 12\), hence \(6y = 12\), so \(y = 2\).
07

Find x and z Using y

Substitute \(y = 2\) back into the equations to find \(x\) and \(z\). Since \(x = 2y = 4\) and \(z = -\frac{x}{2} = -2\).
08

Confirm the Solution Satisfies the Constraint

Check that the values \(x = 4\), \(y = 2\), and \(z = -2\) satisfy the constraint \(2x + y - z = 12\): \(2(4) + 2 - (-2) = 8 + 2 + 2 = 12\), which holds true.
09

Evaluate the Objective Function

Calculate the value of the function \(f(x, y, z) = x^2 + y^2 + z^2\) at the point \(x = 4\), \(y = 2\), \(z = -2\): \(f(4, 2, -2) = 4^2 + 2^2 + (-2)^2 = 16 + 4 + 4 = 24\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Constrained Optimization
Constrained optimization is a fundamental concept where we aim to find the optimal solution of a function subject to certain limitations or restrictions. In this exercise, the goal is to minimize the multivariable function \(f(x, y, z) = x^2 + y^2 + z^2\). The constraint given is \(2x + y - z = 12\). This means that instead of freely finding the minima of the function, we're limited by a specific condition that must be satisfied.

In real-world scenarios, such constraints are common. For example, maximizing profit involves constraints such as limited resources or budget caps. Constrained optimization helps by giving us a systematic way to incorporate these restrictions, ensuring the solutions are both optimal and feasible. The Lagrange multiplier method is a powerful technique used to solve these problems using calculus.

Lagrange multipliers help convert a constrained problem into a form where traditional calculus techniques can be used. Instead of tackling the constraint separately, it becomes part of a new function, allowing us to find solutions that satisfy both the function and the constraint simultaneously.
Calculus
Calculus is the mathematical study of change, and it plays a critical role in understanding optimization problems. It provides the tools needed to investigate the behavior of multivariable functions. With calculus, we can examine how functions behave, change, and how extremes can be located. In the context of this exercise, derivatives are used to find where the function exhibits a minimum value under the given condition.

The technique of using derivatives to set up equations forms the basis of finding extremum points. For constrained problems, the gradient of the Lagrangian (a new function combining both the original function and the constraint) is computed. Partial derivatives of this composite function give us a system of equations when set to zero, which leads us towards potential solutions. Calculus allows for the use of these partial derivatives to analyze and optimize functions with several variables (multivariable functions).

Understanding these fundamentals of calculus is crucial. This knowledge helps manipulate derivatives and work with multivariable functions systematically. Each step of setting the gradient equal to zero translates to ensuring that the function levels do not change, thereby indicating extremes.
Multivariable Functions
Multivariable functions are functions of more than one variable and are prevalent in many areas such as physics, engineering, and economics. In the exercise provided, \(f(x, y, z) = x^2 + y^2 + z^2\) is a multivariable function with three variables—\(x\), \(y\), and \(z\).

The optimization of such functions involves analyzing how changes in these variables affect the overall function value. Multivariable calculus allows us to extend the ideas of calculus to functions that depend on several variables. We use partial derivatives to understand how the function changes with respect to each variable independently.

In practice, every variable in a multivariable function can represent a different dimension. Thus, planning and decision-making need to account for several factors or variables. Solving multivariable problems requires careful consideration of all these interacting variables. The use of gradients, as in Lagrange multipliers, provides insight into how to navigate these functions to find optimal solutions amidst constraints.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Evaluate each iterated integral. $$ \int_{1}^{3} \int_{0}^{2}(x+y) d y d x $$

Solve each using Lagrange multipliers. (The stated extreme values do exist.) A one-story building is to have 8000 square feet of floor space. The front of the building is to be made of brick, which costs \(\$ 120\) per linear foot, and the back and sides are to be made of cinderblock, which costs only \(\$ 80\) per linear foot. a. Find the length and width that minimize the cost of the building. [Hint: The cost of the building is the length of the front, back, and sides, each times the cost per foot for that part. Minimize this subject to the area constraint.] b. Evaluate and give an interpretation for \(|\lambda| .\)

Solve each using Lagrange multipliers. (The stated extreme values do exist.) For each Cobb-Douglas production function \(P\) and isocost line (budget constraint, in dollars), find the amounts of labor \(L\) and capital \(K\) that maximize production, and also find the maximum production. Then evaluate and give an interpretation for \(|\lambda|\) and use it to answer the question. a. Maximize \(P=180 L^{1 / 2} K^{1 / 2}\) with budget constraint \(45 L+20 K=2520\). b. Evaluate and give an interpretation for \(|\lambda|\). c. Approximate the increase in production if the budget is increased by \(\$ 50\).

Find the total differential of each function. $$ g(x, y)=\frac{x}{y} $$

To estimate heating and air conditioning costs, it is necessary to know the volume of a building. A conference center has a curved roof whose height is \(f(x, y)=40-0.006 x^{2}+0.003 y^{2} .\) The building sits on a rectangle extending from \(x=-50\) to \(x=50\) and \(y=-100\) to \(y=100\). Use integration to find the volume of the building. (All dimensions are in feet.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.