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Find each indefinite integral by the substitution method or state that it cannot be found by our substitution formulas. $$ \int\left(x^{2}+1\right)^{4} 5 x d x $$

Short Answer

Expert verified
\( \int (x^2+1)^4 \cdot 5x \, dx = \frac{(x^2+1)^5}{2} + C \).

Step by step solution

01

Identify the Inner Function for Substitution

In the integral \( \int (x^2+1)^4 \cdot 5x \, dx \), the expression \( x^2 + 1 \) is inside the power, which suggests that it should be our substitution candidate. Let \( u = x^2 + 1 \).
02

Determine the Derivative of the Inner Function

Differentiate the chosen substitution \( u = x^2 + 1 \) with respect to \( x \). We get \( \frac{du}{dx} = 2x \), so \( du = 2x \, dx \).
03

Solve for the Differential \( dx \)

Since we have \( du = 2x \cdot dx \), solve for \( dx \) in terms of \( du \) to match the form of the integral. This gives us \( dx = \frac{du}{2x} \).
04

Substitute into the Integral

Substitute the values from Steps 1-3 into the original integral. Replace \( x^2 + 1 \) with \( u \) and replace \( dx \) with \( \frac{du}{2x} \). The integral becomes: \( \int (u^4) \, \frac{5x}{2x} \, du \).
05

Simplify and Integrate

Simplify the fraction \( \frac{5x}{2x} \) to \( \frac{5}{2} \). The integral now is \( \frac{5}{2} \int u^4 \, du \). Integrate this to get \( \frac{5}{2} \cdot \frac{u^5}{5} + C = \frac{u^5}{2} + C \).
06

Substitute Back the Original Variable

Replace \( u \) with \( x^2 + 1 \) to return to the original variable. The solution to the indefinite integral becomes: \( \frac{(x^2 + 1)^5}{2} + C \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Substitution Method
The substitution method is a powerful technique in calculus that helps us integrate more complex functions by simplifying them. Essentially, it involves replacing part of the integrand (the expression being integrated) with a single variable to make the integral easier to evaluate.
When preparing for substitution, identify an inner function of the integrand that, when differentiated, resembles the remaining parts of the integrand. In our exercise, the function inside the power is \( x^2 + 1 \), which we set as \( u \). By doing this, the complexity of the exponent and derivative within the original integral becomes more manageable.
For substitution, calculate the derivative of the chosen inner function. In our case, the derivative of \( u = x^2 + 1 \) is \( \frac{du}{dx} = 2x \), helping us transform our variable of integration \( dx \) in simpler terms. The differential \( du \) takes the place of complex parts involving \( dx \).
Use this transformation to rewrite the integral in terms of \( u \). This often simplifies the integral into a basic form that's straightforward to evaluate. Always remember to convert back to the original variable at the end by substituting back \( x \) for \( u \) once integration is completed.
Indefinite Integrals
Indefinite integrals represent the family of all antiderivatives of a given function. They are written using the integral symbol \( \int \), without specified upper or lower limits. The result of an indefinite integral is a function plus an arbitrary constant \( C \).
In solving indefinite integrals, the main goal is to find the function whose derivative matches the integrand. The substitution method, as used in this exercise, can turn a challenging integral problem into a more familiar one, making it much easier to find the antiderivative.
Here's an important aspect: indefinite integrals always include the constant of integration \( C \). This constant accounts for all possible shifts of the antiderivative function along the vertical axis, representing the complete set of solutions.
  • Recognize functions suitable for substitution.
  • Make careful transformations using substitutions.
  • Always add the integration constant \( C \) at the end of your process.
Calculus Problem Solving
Calculus problem solving often requires using various techniques tailored to the specific form of the function you're working with. It requires an understanding of the function behavior, potential substitutions, and recognizing patterns that repeat across different problems.
One core skill is learning to identify and use integration techniques effectively. In the exercise, we used substitution, which can seamlessly transform a complex problem into a simpler one, especially when dealing with compositions of functions.
When working through calculus problems, it's essential to:
  • Understand the problem deeply, identifying possible methods to simplify it.
  • Use algebraic manipulations, like factoring and expanding, to reformulate the problem.
  • Be patient with applying multiple steps and double-checking each transformation.
  • Practice regularly on similar problems to solidify understanding and discover new solving strategies.
Success in calculus comes from approaching problems systematically, leveraging known strategies like substitution, and maintaining flexibility to adapt new methods as needed.

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Most popular questions from this chapter

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