Chapter 4: Problem 46
For each function, find the indicated expressions. \(f(x)=x^{4} \ln x\) find \(\quad\) a. \(f^{\prime}(x) \quad\) b. \(f^{\prime}(1)\)
Short Answer
Expert verified
a. \( f'(x) = 4x^3 \ln x + x^3 \); b. \( f'(1) = 1 \).
Step by step solution
01
Identify the Parts of the Function
The given function is a product of two components: a power function and a logarithmic function. Specifically, it is expressed as \( f(x) = x^4 \ln x \). Here, \( x^4 \) is the algebraic component, and \( \ln x \) is the logarithmic component. We'll denote these components as \( u \) and \( v \). Let \( u = x^4 \) and \( v = \ln x \).
02
Use the Product Rule for Differentiation
To find the derivative \( f'(x) \), apply the product rule of differentiation: if \( f(x) = u(x) \cdot v(x) \), then \( f'(x) = u'(x)v(x) + u(x)v'(x) \). Identify the derivatives of the components: \( u'(x) = \frac{d}{dx}(x^4) = 4x^3 \) and \( v'(x) = \frac{d}{dx}(\ln x) = \frac{1}{x} \).
03
Calculate the Derivative Expression
Substitute \( u(x) \), \( u'(x) \), \( v(x) \), and \( v'(x) \) into the product rule formula. This gives:\[ f'(x) = (4x^3)(\ln x) + (x^4)\left(\frac{1}{x}\right) \]Simplify the expression:\[ f'(x) = 4x^3 \ln x + x^3 \]
04
Evaluate the Derivative at x = 1
Now, find \( f'(1) \) by substituting \( x = 1 \) into the derivative \( f'(x) = 4x^3 \ln x + x^3 \):\[ f'(1) = 4(1)^3 \ln(1) + (1)^3 \]Since \( \ln(1) = 0 \), the expression simplifies to:\[ f'(1) = 4 \cdot 0 + 1 = 1 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Product Rule
The product rule is a fundamental technique in calculus used for differentiating functions that are products of two or more terms. When you have a function like \( f(x) = u(x) \cdot v(x) \), where \( u(x) \) and \( v(x) \) are both functions of \( x \), the derivative is calculated using the formula:
When applying the product rule, it's crucial to correctly identify and differentiate each component to ensure accurate results. In our example, \( u = x^4 \) and \( v = \ln x \), leading to derivatives \( u'(x) = 4x^3 \) and \( v'(x) = \frac{1}{x} \). Substituting into the product rule gives the result for the derivative of the entire product.
- \( f'(x) = u'(x)v(x) + u(x)v'(x) \)
When applying the product rule, it's crucial to correctly identify and differentiate each component to ensure accurate results. In our example, \( u = x^4 \) and \( v = \ln x \), leading to derivatives \( u'(x) = 4x^3 \) and \( v'(x) = \frac{1}{x} \). Substituting into the product rule gives the result for the derivative of the entire product.
Logarithmic Functions
Logarithmic functions are functions of the form \( f(x) = \ln x \), where \( \ln x \) represents the natural logarithm of \( x \). The natural logarithm is the inverse of the exponential function \( e^x \). It has special properties that make it particularly useful in calculus:
- Its derivative is particularly simple: for \( f(x) = \ln x \), \( f'(x) = \frac{1}{x} \).
- Logarithms help simplify multiplication into addition, which is useful for various mathematical manipulations.
Polynomial Functions
Polynomial functions are expressions that consist of variables raised to positive integer powers. For example, a simple polynomial function could be \( x^4 \). These functions are fundamental in calculus because of their simplicity and predictable patterns:
- The derivative of a polynomial function is defined by the power rule: if \( f(x) = ax^n \), then \( f'(x) = nax^{n-1} \).
- This rule makes differentiation straightforward because it allows you to systematically reduce the power of \( x \) by one and multiply by the original power.