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Find the derivative of each function. $$ f(x)=\ln \left(x^{3}+1\right) $$

Short Answer

Expert verified
The derivative is \( \frac{3x^2}{x^3 + 1} \).

Step by step solution

01

Identify the Function and its Composition

The given function is \( f(x) = \ln(x^3 + 1) \). This function is the natural logarithm of \( x^3 + 1 \). Notice that this is a composite function, meaning it involves a function within another function: the outer function is \( \ln(u) \) and the inner function is \( u = x^3 + 1 \).
02

Apply the Chain Rule

To find the derivative of a composite function, we use the chain rule, which states that the derivative of \( f(g(x)) \) is \( f'(g(x)) \cdot g'(x) \). We let \( u = x^3 + 1 \), so the outer function becomes \( f(u) = \ln(u) \) with \( f'(u) = \frac{1}{u} \).
03

Differentiate the Outer Function

Differentiate the outer function \( f(u) = \ln(u) \) with respect to \( u \). The derivative is \( \frac{d}{du}[\ln(u)] = \frac{1}{u} \). Substitute back \( u = x^3 + 1 \), giving \( \frac{1}{x^3 + 1} \).
04

Differentiate the Inner Function

Differentiate the inner function \( u = x^3 + 1 \) with respect to \( x \). The derivative is \( \frac{d}{dx}[x^3 + 1] = 3x^2 \).
05

Combine Derivatives Using the Chain Rule

Apply the chain rule by multiplying the derivative of the outer function by the derivative of the inner function: \( \frac{df}{dx} = \frac{1}{x^3 + 1} \cdot 3x^2 \).
06

Arrange the Final Expression

Simplify the expression to get the derivative of the original function: \( \frac{df}{dx} = \frac{3x^2}{x^3 + 1} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental tool for differentiation in calculus, particularly when you are dealing with composite functions. It allows us to find the derivative of a function that is made by combining two or more functions. A composite function is essentially a function within another function, and the chain rule helps us tackle these complex structures by breaking them down into simpler parts.

Here's how it works: when you have a function of the form \( f(g(x)) \), the chain rule tells us to first take the derivative of the outer function \( f \) with respect to \( g \), and then multiply it by the derivative of the inner function \( g \) with respect to \( x \). This is written as:
  • \( f'(g(x)) \cdot g'(x) \)
In the context of the exercise, we used the chain rule to differentiate the natural logarithm function \( \ln(x^3 + 1) \). The outer function \( f(u) = \ln(u) \) was differentiated first, then multiplied by the derivative of the inner function \( g(x) = x^3 + 1 \). This strategic breakdown simplifies the process and guides us to the correct solution.
Composite Function
Composite functions are an intriguing part of calculus. They occur when one function is nested inside another, essentially creating a function of a function. In mathematics, this is commonly expressed as \( f(g(x)) \), where \( g(x) \) is the inner function and \( f \) is the outer function.

Understanding composite functions is crucial because they appear often in calculus problems, and usually, they require a special approach for differentiation, such as the chain rule. In the problem provided, \( f(x) = \ln(x^3 + 1) \) is a perfect example of a composite function:
  • The outer function: \( \ln(u) \), where \( u \) represents another function.
  • The inner function: \( x^3 + 1 \), which is the expression inputted inside the \( \ln \) function.
By identifying both the inner and outer components, we can apply appropriate calculus techniques, like the chain rule, to find the derivative.
Natural Logarithm
Natural logarithms, denoted as \( \ln(x) \), are logarithms with a base of \( e \), where \( e \) is a mathematical constant approximately equal to 2.71828. They are fundamental in various branches of mathematics and appear frequently in calculus problems, given their useful properties, particularly for differentiation and integration.

For any logarithmic function, finding its derivative is an essential skill. Specifically, the derivative of \( \ln(x) \) with respect to \( x \) is \( \frac{1}{x} \). This straightforward rule is instrumental in differentiating more complex logarithmic functions.

In our exercise, the function involved a natural logarithm of a composite form \( \ln(x^3 + 1) \). To differentiate it, we applied the chain rule, using the property that the derivative of \( \ln(u) \) with respect to \( u \) is \( \frac{1}{u} \), then multiplied it by the derivative of the inner function. This method yields the final derivative expression, illustrating the elegance and power of natural logarithms in calculus.

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