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Find functions \(f\) and \(g\) such that the given function is the composition \(f(g(x))\). $$ \left(\frac{x+1}{x-1}\right)^{4} $$

Short Answer

Expert verified
\(f(x) = x^4\) and \(g(x) = \frac{x+1}{x-1}\).

Step by step solution

01

Identify the Outer Function

The given expression is \( \left(\frac{x+1}{x-1}\right)^4 \). We first recognize this as the outer function, which is an expression raised to a power. Here, the outer function can be expressed as \( f(u) = u^4 \), where \( u \) is some function of \( x \).
02

Identify the Inner Function

Next, we determine what \( u \) must be to match the form of the given expression. In this case, \( u \) corresponds to \( \frac{x+1}{x-1} \). Thus, the inner function is \( g(x) = \frac{x+1}{x-1} \).
03

Confirm the Composition

We need to ensure that composing \( f \) and \( g \) results in the original function. Substitute \( g(x) \) into \( f(u) \): \( f(g(x)) = \left(\frac{x+1}{x-1}\right)^4 \). This matches the original function given in the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Outer Function
In mathematics, the "outer function" in function composition is the function that is applied last. It's like the outer layer of a sandwich that wraps everything inside. For function composition, the outer function is typically denoted as \( f \). When we deal with a composite function like \( f(g(x)) \), \( f \) is the outer function.
In our exercise, the outer function is \( f(u) = u^4 \). Here, the letter \( u \) signifies the result of the inner function, which will be fed into this outer function. The key role of the outer function is to transform the result of the inner function by applying its own operation, such as raising it to the fourth power in our problem.
Understanding the outer function is essential because it dictates the transformation performed on the input received from the inner function. It completes the function composition by producing the final result. Always ask yourself, what is being done to the output of the inner function? That's where understanding the outer function begins.
Inner Function
The "inner function" is the function applied first in the process of function composition. It's like adding the ingredients inside the outer layer in the sandwich analogy. The inner function is usually represented by \( g \) in compositions such as \( f(g(x)) \).
In our particular exercise, the inner function is \( g(x) = \frac{x+1}{x-1} \). This function takes the input \( x \), processes it, and passes the result to the outer function. The role of the inner function is crucial as it determines the initial transformation before the outer function acts on its output.
Identifying the inner function involves understanding how the original expressions are structured before being altered by the outer function. In this way, the inner function provides the foundational value for the composite function, setting the stage for what the outer function will do next.
Composite Function
Function composition is a powerful mathematical operation that combines two functions to form a third one, known as the composite function. In the format of \( f(g(x)) \), this composite function involves applying the inner function \( g \) first and then applying the outer function \( f \) on the result. Think of it as a sequence of transformations.
For the given problem, the composite function is \( f(g(x)) = \left(\frac{x+1}{x-1}\right)^4 \). Here, we first calculate \( g(x) = \frac{x+1}{x-1} \), and then apply the outer function \( f(u) = u^4 \) to this output. The composite function brings together both transformations into a single process.
In function compositions, it's essential to understand the order of operations. The inner function prepares the input by transforming \( x \), and the outer function refines it to achieve the desired outcome. Recognizing this order helps in constructing and solving problems related to composite functions effectively.

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Most popular questions from this chapter

Pollution The carbon monoxide level in a city is predicted to be \(0.02 x^{3 / 2}+1\) ppm (parts per million), where \(x\) is the population in thousands. In \(t\) years the population of the city is predicted to be \(x(t)=12+2 t\) thousand people. Therefore, in \(t\) years the carbon monoxide level will be $$P(t)=0.02(12+2 t)^{3 / 2}+1 \quad \text { ppm }$$ Find \(P^{\prime}(2)\), the rate at which carbon monoxide pollution will be increasing in 2 years.

Find \(f^{\prime}(x)\) by using the definition of the derivative. [Hint: See Example 4.] $$ \begin{array}{l} \text { } f(x)=x^{4} \\ \text { [Hint: Use } \quad(x+h)^{4}= \\ x^{4}+4 x^{3} h+6 x^{2} h^{2}+4 x h^{3}+h^{4} \end{array} $$

For each function: a. Find \(f^{\prime}(x)\) using the definition of the derivative. b. Explain, by considering the original function, why the derivative is a constant. $$ \begin{array}{l} f(x)=m x+b\\\ (m \text { and } b \text { are constants) } \end{array} $$

a. Graph the function \(f(x)=x^{2}-3 x+5\) on the window \([-10,10]\) by \([-10,10]\). Then use the DRAW menu to graph the TANGENT line at \(x=2\). Your screen should also show the equation of the tangent line. (If you did Exercise 45, this equation for the tangent line should agree with the one you found there.) b. Add to your graph the tangent line at \(x=1\), and the tangent lines at any other \(x\) -values that you choose.

Beverton-Holt Recruitment Curve Some organisms exhibit a density-dependent mortality from one generation to the next. Let \(R>1\) be the net reproductive rate (that is, the number of surviving offspring per parent), let \(x>0\) be the density of parents, and \(y\) be the density of surviving offspring. The Beverton-Holt recruitment curve is $$ y=\frac{R x}{1+\left(\frac{R-1}{K}\right) x} $$ where \(K>0\) is the carrying capacity of the organism's environment. Show that \(\frac{d y}{d x}>0\), and interpret this as a statement about the parents and the offspring.

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