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Find the derivative of each function in two ways: a. Using the Quotient rule. b. Simplifying the original function and using the Power Rule. Your answers to parts (a) and (b) should agree. $$ \frac{x^{8}}{x^{2}} $$

Short Answer

Expert verified
The derivative is \( 6x^5 \) using both methods.

Step by step solution

01

Identify the Quotient Rule Formula

The quotient rule states that if you have a function in the form \( \frac{u}{v} \), then the derivative \( \left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2} \). Here, \( u = x^8 \) and \( v = x^2 \).
02

Differentiate Using the Quotient Rule

First, find the derivatives \( u' \) and \( v' \). Since \( u = x^8 \), \( u' = 8x^7 \). Since \( v = x^2 \), \( v' = 2x \). Apply the quotient rule: \[ (x^8/x^2)' = \frac{8x^7 \cdot x^2 - x^8 \cdot 2x}{(x^2)^2} \]. Simplifying, \[ = \frac{8x^9 - 2x^9}{x^4} = \frac{6x^9}{x^4} = 6x^5 \].
03

Simplify the Original Function

Before differentiation, simplify \( \frac{x^8}{x^2} \) to \( x^{8-2} = x^6 \).
04

Differentiate the Simplified Function Using the Power Rule

Apply the power rule to the simplified function \( x^6 \) which states that \( \frac{d}{dx}[x^n] = nx^{n-1} \). Therefore, \( \frac{d}{dx}[x^6] = 6x^5 \).
05

Verify Consistency in Answers

Both methods produced the same derivative: \( 6x^5 \). Thus, the computations are consistent and correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
The quotient rule is a fundamental technique in calculus employed for differentiating functions that are expressed as fractions, specifically when one function is divided by another. Imagine you have a complex function structured as \( \frac{u}{v} \). To find its derivative, you'd use the formula:
\[\left( \frac{u}{v} \right)' = \frac{u'v - uv'}{v^2}.\]This method systematically helps in determining how changes in both the numerator's and the denominator's functions affect the rate of change of the entire function itself. From our example, we identified \( u = x^8 \) and \( v = x^2 \). By differentiating these, we found \( u' = 8x^7 \) and \( v' = 2x \). Plugging these into the quotient rule gives us:
  • \( u'v = 8x^7 \cdot x^2 = 8x^9 \)
  • \( uv' = x^8 \cdot 2x = 2x^9 \)
  • Thus, the derivative becomes \( \frac{8x^9 - 2x^9}{x^4} = \frac{6x^9}{x^4} = 6x^5 \)
This shows the power of the quotient rule, providing a structured approach to such differentiation problems.
Power Rule
The power rule is one of the simplest yet most useful rules for finding derivatives of polynomial expressions. It states that if you have a function \( x^n \), its derivative is calculated as:
\[\frac{d}{dx}[x^n] = nx^{n-1}.\]This rule simplifies the process by bringing down the exponent as a coefficient and reducing the exponent by one. For instance, with the simplified function \( x^6 \) derived from \( \frac{x^8}{x^2} = x^6 \), applying the power rule gives:
\[\frac{d}{dx}[x^6] = 6x^5,\]which matches the result obtained using the quotient rule. This consistency confirms the correctness of both approaches. The power rule is straightforward and is often the quickest method if you can simplify the equation before differentiation.
Simplifying Functions
Simplifying a function before differentiating can transform complex problems into simpler ones, potentially saving time and reducing errors. The approach involves reducing the complexity of the expression, either by canceling common terms or combining like terms. In our problem, the original fraction \( \frac{x^8}{x^2} \) simplifies directly to \( x^{8-2} = x^6 \). This reduction makes it easier to apply the power rule as opposed to dealing with a more complicated fraction.When you simplify first, you often make the derivative process much more intuitive. Furthermore, simplification can help clarify solutions, making them easier to check and understand. This approach is especially powerful when dealing with algebraic expressions where terms can be directly reduced before moving forward to differentiation.

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Most popular questions from this chapter

Find \(f^{\prime}(x)\) by using the definition of the derivative. [Hint: See Example 4.] $$ \begin{array}{l} \text { } f(x)=(x+a)^{2}\\\ \left(a \text { is a constant.) [Hint: First expand }(x+a)^{2}\right. \text { .] } \end{array} $$

Electronics Index The S\&P index for the Consumer Electronics Subindustry for recent years is shown below. The index is approximated by the function \(f(x)=13 x^{2}-82 x+150\), where \(x\) stands for years since 2006 . a. Find \(f^{\prime}(x)\) using the definition of the derivative. b. Evaluate the derivative at \(x=1\) and interpret the result. c. Find the rate of change of the index in 2010 .

Pollution The carbon monoxide level in a city is predicted to be \(0.02 x^{3 / 2}+1\) ppm (parts per million), where \(x\) is the population in thousands. In \(t\) years the population of the city is predicted to be \(x(t)=12+2 t\) thousand people. Therefore, in \(t\) years the carbon monoxide level will be $$P(t)=0.02(12+2 t)^{3 / 2}+1 \quad \text { ppm }$$ Find \(P^{\prime}(2)\), the rate at which carbon monoxide pollution will be increasing in 2 years.

Derive the Quotient Rule from the Product Rule as follows. a. Define the quotient to be a single function, $$ Q(x)=\frac{f(x)}{g(x)} $$ b. Multiply both sides by \(g(x)\) to obtain the equation \(Q(x) \cdot g(x)=f(x) .\) c. Differentiate each side, using the Product Rule on the left side. d. Solve the resulting formula for the derivative \(Q^{\prime}(x) .\) e. Replace \(Q(x)\) by \(\frac{f(x)}{g(x)}\) and show that the resulting formula for \(Q^{\prime}(x)\) is the same as the Quotient Rule. Note that in this derivation when we differentiated \(Q(x)\) we assumed that the derivative of the quotient exists, whereas in the derivation on pages \(135-136\) we proved that the derivative exists.

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