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For each pair of functions \(f(x)\) and \(g(x)\), find and fully simplify a. \(f(g(x))\) and b. \(g(f(x))\) $$ f(x)=x^{3}+1 ; g(x)=\sqrt[3]{x-1} $$

Short Answer

Expert verified
Both \(f(g(x))\) and \(g(f(x))\) simplify to \(x\).

Step by step solution

01

Understand the Composition of Functions

Composition of functions involves applying one function to the results of another. To find \( f(g(x)) \) and \( g(f(x)) \), we will substitute \( g(x) \) into \( f(x) \) and \( f(x) \) into \( g(x) \).
02

Find \(f(g(x))\)

To find \( f(g(x)) \), substitute \( g(x) = \sqrt[3]{x-1} \) into \( f(x) = x^3 + 1 \). This gives:\[ f(g(x)) = f(\sqrt[3]{x-1}) = (\sqrt[3]{x-1})^3 + 1. \]
03

Simplify \( (\sqrt[3]{x-1})^3 + 1 \)

The expression \( (\sqrt[3]{x-1})^3 \) simplifies to \( x - 1 \), since cubing the cube root returns the original value inside the radical. Thus the expression becomes:\[ f(g(x)) = x - 1 + 1 = x. \]
04

Find \(g(f(x))\)

To find \( g(f(x)) \), substitute \( f(x) = x^3 + 1 \) into \( g(x) = \sqrt[3]{x-1} \). This gives:\[ g(f(x)) = g(x^3 + 1) = \sqrt[3]{(x^3 + 1) - 1}. \]
05

Simplify \( \sqrt[3]{(x^3 + 1) - 1} \)

Simplify the expression \( \sqrt[3]{(x^3 + 1) - 1} \):\[ (x^3 + 1) - 1 = x^3, \] so the expression becomes:\[ g(f(x)) = \sqrt[3]{x^3}. \]
06

Simplify \( \sqrt[3]{x^3} \)

The cube root of \( x^3 \) simplifies to \( x \), because the cube root and the cubing are inverse operations:\[ g(f(x)) = x. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Function Operations
In mathematics, function operations allow you to combine two or more functions in various ways to form new functions. One of the most interesting operations is the composition of functions. This involves plugging the output of one function into another function. In our exercise, with functions \( f(x) = x^3 + 1 \) and \( g(x) = \sqrt[3]{x-1} \), you can see this operation in action.

With compositions like \( f(g(x)) \), we take the result of \( g(x) \) and use it as the input to \( f(x) \). Similarly, with \( g(f(x)) \), the function \( f(x) \) becomes the input into \( g(x) \). This sequence of actions allows for intricate transformations of the input value, showcasing the beauty and power of function operations. Not only does this deepen understanding of how functions interact, but it also enhances problem-solving skills.
Simplifying Expressions
Simplifying expressions is a fundamental skill in mathematics that makes complicated equations or expressions easier to work with. During the composition of functions, simplification is crucial to arrive at the cleanest form of your answer.

For example, when finding \( f(g(x)) \) in the given exercise, you initially get \( f(\sqrt[3]{x-1}) = (\sqrt[3]{x-1})^3 + 1 \). Simplifying \( (\sqrt[3]{x-1})^3 \) results in \( x - 1 \), as the operations of taking a cube root and cubing cancel each other out. Adding the numbers gives us \( x \).

Similarly, for \( g(f(x)) \), when you simplify \( \sqrt[3]{(x^3 + 1) - 1} \), you get \( \sqrt[3]{x^3} \). Solving this gives you \( x \), since taking the cube root and then cubing are inverse operations. Through these operations, you turn complex-looking compositions into very straightforward results.
Mathematical Functions
Mathematical functions are like machines that transform input values into output values via a rule or an equation. They are a staple in various fields of science and everyday calculations.

In our example, the functions \( f(x) = x^3 + 1 \) and \( g(x) = \sqrt[3]{x-1} \) show different ways how functions can manipulate an input value. \( f(x) \) cubes the number and adds one, while \( g(x) \) performs the cube root operation after subtracting one.

These functions could represent real-world phenomena, like \( f(x) \) describing the volume of a cube given side length plus a constant, and \( g(x) \) representing a chemical reaction where reducing one unit of an input affects the final result in the form of a cube root. Understanding functions and their compositions allows one to model various natural processes, making them a key concept in mathematical analysis and application.

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Most popular questions from this chapter

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