/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 \(35-52 .\) Solve each equation ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

\(35-52 .\) Solve each equation by factoring or the Quadratic Formula, as appropriate. $$ x^{2}-6 x-7=0 $$

Short Answer

Expert verified
The solutions are \(x = 7\) and \(x = -1\).

Step by step solution

01

Identify the Equation Type

The given equation is a quadratic equation in the form \( ax^2 + bx + c = 0 \). Here, \( a = 1 \), \( b = -6 \), and \( c = -7 \).
02

Decide the Solution Method

We choose to factor the equation because it can be easily factored into two binomials. If factoring is difficult, the Quadratic Formula can also be used.
03

Factor the Quadratic Equation

To factor \( x^2 - 6x - 7 = 0 \), we look for two numbers that multiply to \(-7\) (the constant term \(c\)) and add to \(-6\) (the middle term \(b\)). These numbers are \(-7\) and \(1\). The factored form is \((x - 7)(x + 1) = 0\).
04

Solve for x Using the Zero Product Property

Set each factor equal to zero: \(x - 7 = 0\) or \(x + 1 = 0\). Solve these to find \(x = 7\) and \(x = -1\).
05

Verify the Solutions

Substitute \(x = 7\) and \(x = -1\) back into the original equation to ensure they satisfy it. In both cases, \(x^2 - 6x - 7 = 0\) is true, confirming the solutions are correct.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Quadratic Equations
When dealing with quadratic equations, a common method of solving them is factoring. Quadratic equations are typically in the form of \( ax^2 + bx + c = 0 \). Our task is to express it as a product of two binomials. Once factored, solving the equation becomes straightforward.

In the equation \( x^2 - 6x - 7 = 0 \), we specifically look for two numbers that multiply to \(-7\) and add up to \(-6\). These are the coefficients from which we will derive our binomials. For this equation:
  • - Multiplying to \(-7\) comes from the constant term \(c\).
  • - Adding to \(-6\) comes from the middle term \(b\).
Once identified, these numbers are \(-7\) and \(1\), leading to the factorization: \( (x - 7)(x + 1) = 0 \).

This step is crucial, as it creates the pathway to our solutions.
Zero Product Property
The Zero Product Property is a fundamental principle used when solving factored quadratic equations. It states that if the product of two numbers is zero, at least one of the multiplicands must be zero. This property allows us to solve for \(x\) once we have factored the quadratic equation.

For \( (x - 7)(x + 1) = 0 \), we apply this property by setting each factor equal to zero:
  • \(x - 7 = 0\)
  • \(x + 1 = 0\)
Solving these individual equations gives us the values of \(x\) that satisfy the original quadratic equation:
, ,
By employing this property, we break down a potentially complex quadratic problem into two much simpler linear equations.
Solving Quadratic Equations
Solving quadratic equations is a skill that opens the door to understanding a wide range of mathematical concepts. The ultimate goal of solving a quadratic equation is to find the values of \(x\) that satisfy the equation.

For the equation \( x^2 - 6x - 7 = 0 \), we found the solutions through factoring and applying the Zero Product Property:
  • The initial step involved recognizing the equation as quadratic.
  • Next, we factored it into \( (x - 7)(x + 1) = 0 \).
  • We then applied the Zero Product Property to find \(x = 7\) and \(x = -1\).
To finalize, it's important to verify these solutions by substituting them back into the original equation. If both actual solutions satisfy \(x^2 - 6x - 7 = 0\), then the solutions are correct. Indeed, substituting confirms that both solutions work, ensuring the accuracy of our work.

Understanding these processes builds a strong foundation for further mathematical exploration.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

$$ \text { How do the graphs of } f(x) \text { and } f(x+10)+10 \text { differ? } $$

$$ \text { How do the graphs of } f(x) \text { and } f(x+10) \text { differ? } $$

ATHLETICS: Juggling If you toss a ball \(h\) feet straight up, it will return to your hand after \(T(h)=0.5 \sqrt{h}\) seconds. This leads to the juggler's dilemma: Juggling more balls means tossing them higher. However, the square root in the above formula means that tossing them twice as high does not gain twice as much time, but only \(\sqrt{2} \approx 1.4\) times as much time. Because of this, there is a limit to the number of balls that a person can juggle, which seems to be about ten. Use this formula to find: a. How long will a ball spend in the air if it is tossed to a height of 4 feet? 8 feet? b. How high must it be tossed to spend 2 seconds in the air? 3 seconds in the air?

89-90. Some organisms exhibit a density-dependent mortality from one generation to the next. Let \(R>1\) be the net reproductive rate (that is, the number of surviving offspring per parent), let \(x>0\) be the density of parents and \(y\) be the density of surviving offspring. The Beverton-Holt recruitment curve is $$ y=\frac{R x}{1+\left(\frac{R-1}{K}\right) x} $$ where \(K>0\) is the carrying capacity of the environment. Notice that if \(x=K\), then \(y=K\). Show that if \(x

BUSINESS: Break-Even Points and Maximum Profit A sporting goods store finds that if it sells \(x\) exercise machines per day, its costs will be \(C(x)=100 x+3200\) and its revenue will be \(R(x)=-2 x^{2}+300 x\) (both in dollars). a. Find the store's break-even points. b. Find the number of sales that will maximize profit, and the maximum profit.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.