Chapter 1: Problem 30
For each equation, find the slope \(m\) and \(y\) -intercept \((0, b)\) (when they exist) and draw the graph. \(\frac{x}{2}+\frac{y}{3}=1\)
Short Answer
Expert verified
The slope is \(-\frac{3}{2}\), and the y-intercept is 3.
Step by step solution
01
Identify the standard form
The given equation is \( \frac{x}{2} + \frac{y}{3} = 1 \). This is in the form \( Ax + By = C \). Here, \( A = \frac{1}{2} \), \( B = \frac{1}{3} \), and \( C = 1 \).
02
Convert to slope-intercept form
To find the slope and y-intercept, convert the equation to the slope-intercept form \( y = mx + b \). Start by isolating \( y \):\[ \frac{y}{3} = 1 - \frac{x}{2}.\] Multiply everything by 3 to clear the fraction:\[ y = 3 \left(1 - \frac{x}{2}\right). \] Simplify it to \[ y = -\frac{3}{2}x + 3. \]
03
Identify slope and y-intercept
Now that we have the equation in the slope-intercept form \( y = mx + b \), we can easily identify the slope \( m \) and y-intercept \( b \). From \( y = -\frac{3}{2}x + 3 \), the slope \( m \) is \(-\frac{3}{2}\) and the y-intercept \( b \) is 3.
04
Graph the equation
Start by plotting the y-intercept \( (0, 3) \) on the graph. Then, use the slope \( -\frac{3}{2} \) to find another point. From \( (0, 3) \), move down 3 units and to the right 2 units, which lands you at the point \( (2, 0) \). Draw a line through the points \( (0, 3) \) and \( (2, 0) \). This line is the graph of the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Linear Equations
Graphing linear equations is a visual method of representing solutions to equations. When dealing with a linear equation like \( \frac{x}{2} + \frac{y}{3} = 1 \), you first need to understand that it represents a straight line on a coordinate plane. Each point on this line is a solution to the equation.
To graph a linear equation, follow these steps:
To graph a linear equation, follow these steps:
- First, convert the equation into a form that is easier to work with, typically the slope-intercept form, which is \( y = mx + b \).
- The next step is to determine at least two points that the line passes through. This can be done by finding the y-intercept and using the slope to locate another point.
- Once you have these two points, you draw a line through them, which will be the graph of the equation.
Y-Intercept
The y-intercept of a linear equation is the point where the line crosses the y-axis on a graph. In the slope-intercept form \( y = mx + b \), the y-intercept is represented by \( b \). This is because, at the y-intercept, the value of \( x \) is always 0.
For the equation \( y = -\frac{3}{2}x + 3 \), the y-intercept \( b \) is 3. This means that when the line crosses the y-axis, it does so at the point \( (0, 3) \).
Having a clear understanding of the y-intercept is crucial because it gives you a starting point on a graph. From this point, you can easily apply the slope to determine other points on the line. Always remember:
For the equation \( y = -\frac{3}{2}x + 3 \), the y-intercept \( b \) is 3. This means that when the line crosses the y-axis, it does so at the point \( (0, 3) \).
Having a clear understanding of the y-intercept is crucial because it gives you a starting point on a graph. From this point, you can easily apply the slope to determine other points on the line. Always remember:
- The y-intercept tells you the initial value of \( y \) when \( x = 0 \).
- It acts as a key point in plotting linear equations.
Slope Calculation
Slope is a measure of the steepness of a line, depicted as \( m \) in the slope-intercept form \( y = mx + b \). It tells us how much \( y \) changes for a unit change in \( x \). A positive slope means the line rises as \( x \) increases, while a negative slope means it falls.
In our equation, \( y = -\frac{3}{2}x + 3 \), the slope \( m \) is \(-\frac{3}{2}\). Here's how to interpret it:
In our equation, \( y = -\frac{3}{2}x + 3 \), the slope \( m \) is \(-\frac{3}{2}\). Here's how to interpret it:
- The negative sign indicates that for every increase of 2 units in \( x \), \( y \) decreases by 3 units.
- This forms a downward slope from left to right on a graph.
- Start from a known point like the y-intercept \((0, 3)\).
- Apply the slope: Move down 3 units and right 2 units to find another point \((2, 0)\).