/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Evaluate each expression without... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate each expression without using a calculator. $$ \left(\frac{16}{25}\right)^{3 / 2} $$

Short Answer

Expert verified
The expression evaluates to \( \frac{64}{125} \).

Step by step solution

01

Understand the Expression

The expression \( \left(\frac{16}{25}\right)^{3/2} \) involves a fractional BASE raised to a fractional EXPONENT. Let's break this down step by step.
02

Simplify the Base

First, recognize that 16 and 25 are perfect squares. We can express them as \( 16 = 4^2 \) and \( 25 = 5^2 \). Thus, \( \frac{16}{25} = \left(\frac{4}{5}\right)^2 \).
03

Apply the Power of a Power Rule

When you raise a power to another power, you multiply the exponents. The expression becomes: \[ \left(\frac{4}{5}\right)^{2 \times \frac{3}{2}} \] which simplifies to \[ \left(\frac{4}{5}\right)^{3} \].
04

Simplify the Cubed Fraction

Now, raise both the numerator and the denominator of the fraction to the power of 3. This gives us: \[ \frac{4^3}{5^3} = \frac{64}{125} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Perfect Squares
Perfect squares are numbers that can be expressed as the square of an integer. In simpler terms, a perfect square is a number that results from multiplying an integer by itself. For example, 16 is a perfect square because it's equivalent to
  • \( 4 \times 4 = 16 \)
and 25 is a perfect square because
  • \( 5 \times 5 = 25 \).

In the original exercise, it was crucial to recognize that both 16 and 25 are perfect squares, enabling us to express them as powers of 2. This understanding simplifies our problem by allowing the base of the fractional expression \( \left(\frac{16}{25}\right) \) to be written as \( \left(\frac{4}{5}\right)^2 \), making it easier to apply subsequent mathematical rules.
Power of a Power Rule
The power of a power rule is a helpful exponent rule for simplifying expressions. When a base with an exponent is raised to another exponent, you can multiply the two exponents together. This rule is very useful, especially in expressions that involve more than one layer of exponents.

For example, in our expression \( \left(\frac{4}{5}\right)^{2 \times \frac{3}{2}} \), we are raising \( \left(\frac{4}{5}\right)^2 \) to the power of \( \frac{3}{2} \). According to the power of a power rule, you multiply the exponents:
  • \( 2 \times \frac{3}{2} = 3 \).
This results in \( \left(\frac{4}{5}\right)^3 \), simplifying the calculation. Understanding and applying this rule will make dealing with complex expressions much easier.
Cubed Fraction
A cubed fraction involves raising both the numerator and the denominator of a fraction to the power of three. When you encounter a cubed fraction, you simply cube each part separately to get the result.

In our exercise, once we simplified \( \left(\frac{4}{5}\right)^3 \), we need to cube both the numerator and the denominator:
  • The numerator is cubed as \( 4^3 = 64 \).
  • The denominator is cubed as \( 5^3 = 125 \).
After performing these calculations, the expression simplifies to \( \frac{64}{125} \). Cubing fractions may seem tricky at first, but by breaking it down, it becomes quite straightforward.

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Most popular questions from this chapter

Electronic commerce or e-commerce, buying and selling over the Internet, has been growing rapidly. The total value of U.S. e-commerce in recent years in trillions of dollars is given by the exponential function \(f(x)=1.15(1.17)^{x}\), where \(x\) is the number of years since 2004 . Predict total e-commerce in the year 2015 .

$$ \begin{array}{l} \text { For each function, find and simplify }\\\ \frac{f(x+h)-f(x)}{h} . \quad(\text { Assume } h \neq 0 .) \end{array} $$ $$ f(x)=\sqrt{x} $$

SOCIAL SCIENCE: Health Club Attendance A recent study analyzed how the number of visits a person makes to a health club varies with the monthly membership price. It found that the number of visits per year is given approximately by \(v(x)=-0.004 x^{2}+0.56 x+42\), where \(x\) is the monthly membership price. What monthly price maximizes the number of visits?

GENERAL: Seat Belt Use Because of driver education programs and stricter laws, seat belt use has increased steadily over recent decades. The following table gives the percentage of automobile occupants using seat belts in selected years. $$ \begin{array}{lcccc} \hline \text { Year } & 1995 & 2000 & 2005 & 2010 \\ \hline \text { Seat Belt Use (\%) } & 60 & 71 & 81 & 86 \\ \hline \end{array} $$ a. Number the data columns with \(x\) -values \(1-4\) and use linear regression to fit a line to the data. State the regression formula. [Hint: See Example 8.] b. Interpret the slope of the line. From your answer, what is the yearly increase? c. Use the regression line to predict seat belt use in \(2015 .\) d. Would it make sense to use the regression line to predict seat belt use in 2025 ? What percentage would you get?

Find, rounding to five decimal places: a. \(\left(1+\frac{1}{100}\right)^{100}\) b. \(\left(1+\frac{1}{10,000}\right)^{10,000}\) c. \(\left(1+\frac{1}{1,000,000}\right)^{1,000,000}\) d. Do the resulting numbers seem to be approaching a limiting value? Estimate the limiting value to five decimal places. The number that you have approximated is denoted \(e\), and will be used extensively in Chapter 4 .

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