Chapter 6: Problem 5
Evaluate each limit (or state that it does not exist). $$ \lim _{x \rightarrow \infty}\left(2-e^{x / 2}\right) $$
Short Answer
Expert verified
The limit is \(-\infty\).
Step by step solution
01
Understand the Expression
The function we need to evaluate the limit for is \( f(x) = 2 - e^{x/2} \). As \( x \) approaches infinity, we are interested in the behavior of this expression.
02
Analyze the Exponential Term
Consider the exponential term \( e^{x/2} \). As \( x \rightarrow \infty \), the term \( e^{x/2} \) also approaches infinity because any positive power of \( e \) grows without bound as the exponent increases.
03
Evaluate the Limit of the Expression
Given that \( e^{x/2} \to \infty \) as \( x \to \infty \), the expression \( 2 - e^{x/2} \) thus approaches \( 2 - \infty \), which simplifies to \(-\infty \).
04
Conclusion
Since the expression \( 2 - e^{x/2} \to -\infty \) as \( x \to \infty \), the limit is \(-\infty\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Functions
Exponential functions are a fundamental concept in calculus, and understanding their behavior is crucial in many mathematical scenarios. An exponential function takes the general form
In mathematical contexts, especially calculus, the function \( e^{x} \) is particularly significant due to its unique properties in growth and derivatives.
- \( f(x) = a imes b^{x} \)
In mathematical contexts, especially calculus, the function \( e^{x} \) is particularly significant due to its unique properties in growth and derivatives.
- \( e^{x} \) grows extremely rapidly as \( x \) increases.
- It has a derivative that is equal to itself, meaning \( \frac{d}{dx}e^{x} = e^{x} \).
Infinity in Calculus
Infinity is a concept rather than a number, representing an unbounded quantity. In calculus, understanding how functions behave as variables approach infinity is essential for evaluating limits and asymptotic behavior.
When we say \( x \to \infty \), we mean that \( x \) grows larger and larger without bound. Analyzing functions at infinity helps us understand trends or ultimate behaviors.
Consider the function \( e^{x/2} \) in our original exercise. As \( x \) approaches infinity, \( e^{x/2} \) becomes infinitely large. This impacts the expression \( 2 - e^{x/2} \), simplifying to \( 2 - \infty \), which we interpret as \(-\infty\).
When evaluating limits involving infinity, it is essential to consider:
When we say \( x \to \infty \), we mean that \( x \) grows larger and larger without bound. Analyzing functions at infinity helps us understand trends or ultimate behaviors.
Consider the function \( e^{x/2} \) in our original exercise. As \( x \) approaches infinity, \( e^{x/2} \) becomes infinitely large. This impacts the expression \( 2 - e^{x/2} \), simplifying to \( 2 - \infty \), which we interpret as \(-\infty\).
When evaluating limits involving infinity, it is essential to consider:
- If the expression's components have terms that grow infinitely (or diminish infinitely), they significantly impact the result.
- The resultant behavior (like \( -\infty \) in our exercise) indicates that the function becomes unbounded in the negative direction as \( x \to \infty \).
Limit Evaluation Techniques
Limit evaluation in calculus allows us to determine how a function behaves as the input approaches a particular value or infinity. Common techniques include:
The general steps for evaluating such limits include:
- Simplifying the expression using algebraic manipulation.
- Substituting values directly when appropriate.
- Utilizing special limits like limits of exponential and trigonometric functions.
The general steps for evaluating such limits include:
- Identifying the behavior of each component of the function as \( x \to \infty \).
- Determining how these components interact—large terms typically overpower constant terms in influence.
- Simplifying and concluding based on these observations.