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The value of a stamp collection, initially worth $$\$ 1500$$, grows continuously at the rate of $$8 \%$$ per year. Find a formula for its value after t years.

Short Answer

Expert verified
The formula is \( V(t) = 1500 \, e^{0.08t} \).

Step by step solution

01

Understand the Problem

We are given an initial value for a stamp collection, which is $1500, and it grows continuously at a rate of 8% per year. We want to find a formula for its value after \( t \) years.
02

Recognize the Formula to Use

This is a problem involving continuous compounding growth, which is modeled by the exponential growth formula: \[ V(t) = V_0 e^{rt} \]where \( V(t) \) is the value after \( t \) years, \( V_0 \) is the initial value, \( r \) is the growth rate, and \( e \) is the base of the natural logarithms.
03

Identify Given Values

We know the initial value \( V_0 = 1500 \) and the growth rate \( r = 8\% = 0.08 \). These values will be substituted into the exponential growth formula.
04

Substitute Values into the Formula

Substitute the known values into the continuous growth formula:\[ V(t) = 1500 \, e^{0.08t} \]
05

Finalize the Formula

The formula \( V(t) = 1500 \, e^{0.08t} \) is now complete. This formula can be used to calculate the value of the collection at any given time \( t \), in years.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Continuous Compounding
Continuous compounding is a fascinating concept that's quite different from the usual compounding methods we might be familiar with, such as annual or quarterly compounding. When we talk about continuous compounding, we're discussing a process where the interest is calculated and added back to the principal continuously over time. This means that instead of having a set number of times per year when interest is calculated (like once a year or four times a year), the calculation is happening all the time, almost infinitely. The result is that your investment or anything that grows at this rate accumulates very quickly. The mathematical constant 鈥渆鈥 plays a crucial role here. It represents an irrational number, approximately equal to 2.71828, which is the base rate of growth shared by all continuously growing processes.
When applied to finances, biology, or any other field, continuous compounding can dramatically impact the outcome of growth over time.
Growth Rate
The growth rate is a critical component in any growth model, particularly in continuous compounding scenarios. It tells us how fast a quantity increases over a specific period. In the context of continuous growth like in our stamp collection example, the growth rate is often expressed as a percentage.
For instance, an 8% growth rate implies that every year, the value of an investment grows by 8%.In mathematical models, the growth rate is denoted by the symbol \( r \). It's essential to express it in decimal form when plugging it into formulas. So, an 8% growth rate becomes 0.08 in our continuous compounding formula. Understanding how to calculate and interpret the growth rate helps in predicting how fast an investment can grow, which can aid in financial planning and analysis.
Exponential Growth Formula
The exponential growth formula is a powerful tool for predicting how a quantity will change over time when experiencing exponential growth. In our example of the stamp collection, this formula helps us determine the collection's future value given its current value and growth rate. The general form of the exponential growth formula is: \[ V(t) = V_0 \times e^{rt} \]where:
  • \( V(t) \) represents the value at time \( t \).
  • \( V_0 \) is the initial value or starting amount, which is $1500 in our problem.
  • \( r \) is the growth rate, expressed as a decimal (for 8%, use 0.08).
  • \( t \) is the time in years.
  • \( e \) is the base of the natural logarithm, approximately equal to 2.71828.
By inputting these variables into the formula, you can model how the value changes over time, offering insights that are applicable in various fields beyond finance, such as biology, physics, and more.

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