/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Evaluate each limit (or state th... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate each limit (or state that it does not exist). $$ \lim _{x \rightarrow \infty} \frac{1}{x^{2}} $$

Short Answer

Expert verified
The limit is 0.

Step by step solution

01

Understand the Function

The function we are dealing with is a fraction where the numerator is constant (1) and the denominator is a variable squared (\(x^2\)). As \(x\) gets larger, \(x^2\) will grow very quickly because squaring a large number results in an even larger number.
02

Consider the Behavior as x Approaches Infinity

As \(x\) approaches infinity, the denominator \(x^2\) gets larger and larger. Since \(x^2\) is in the denominator, the fraction \(\frac{1}{x^2}\) gets smaller and smaller.
03

Determine the Limit

As \(x\) becomes infinitely large, \(\frac{1}{x^2}\) approaches 0 because the numerator remains 1 (a constant) and the denominator grows without bound. Therefore, the limit of \(\frac{1}{x^2}\) as \(x\) approaches infinity is 0.
04

Conclusion

After evaluating the behavior of \(\frac{1}{x^2}\) as \(x\) approaches infinity, we find that the limit is \(0\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Evaluation
Limits are a fundamental concept in calculus, providing insight into the behavior of functions as they approach specific points or extend towards infinity. When evaluating a limit, the goal is to determine what value a function approaches as the input becomes very large or very small.This is particularly useful for understanding trends, predicting behaviors, or finding boundaries in different functions.

To evaluate a limit, follow these key steps:
  • Identify the function and the specific behavior we're interested in, such as \( ext { as } x \rightarrow ext { some value, or as } x \rightarrow ext { inifinity.} \)
  • Examine the function's structure, as it may hint at its end behavior. For instance, see if it has a highest power term that dominates or if it simplifies into a special form.
  • Apply limit laws and mathematical reasoning to deduce the limit. These laws simplify calculations and confirm results like setting a denominator to zero under specific scenarios.
Using these steps allows the evaluation of complex functions systematically. By doing so, it becomes easier to establish the bounds and behaviors of various mathematical scenarios.
Infinity in Calculus
Infinity in calculus plays a pivotal role when exploring the extremes of function behaviors. It allows us to conceptualize the behavior of a function as it grows indefinitely or approaches a point without limit.Consider an example: as \( x \) heads towards infinity, the function \( \frac{1}{x^2} \) shrinks towards zero. Its diminishing nature makes it increasingly small, yet never quite reaching zero.

Here's what to consider about infinity in calculus:
  • Infinity as a Limit: Functions can "approach" infinity. A notation like \( x \rightarrow ext{infinity} \) describes how \( x \) increases without bound.
  • Results: Considering infinity helps identify the potential finite limit of a function or to deem a limit as not existing, if it diverges indefinitely.
  • Conceptuality: Infinity isn't a number but a notion that helps us warrant certain limits that extend beyond the finite mathematics.
The concept of infinity is vital because it frequently appears in calculus problems, revealing insights into behavior at extreme points.
Rational Functions
Rational functions are quotients composed of two polynomial functions. They feature prominently in calculus due to their diverse properties and behaviors. By understanding them well, one can predict their general behavior, more so around certain points like infinity.A function of the form \( f(x) = \frac{g(x)}{h(x)} \) is a rational function. The numerator \( g(x) \) and the denominator \( h(x) \) are both polynomials. Evaluating their limits often requires examining the relationship between the degrees of these polynomials.

Here are some important aspects to keep in mind about rational functions:
  • Behavior at Infinity: The end behavior of a rational function as \( x \rightarrow \infty \) often depends on the degree comparison between the numerator and the denominator.
  • Singularity Points: These occur when the denominator equals zero, which may result in vertical asymptotes, holes, or limit behaviors that do not exist.
  • Limit Simplification: The highest degree of \( x \) usually dominates the function as \( x \rightarrow \infty \). For example, if the denominator's degree is higher, the function's limit is likely to approach zero.
Understanding rational functions allows students to predict function behaviors near crucial points and tackle practical calculus problems with confidence.

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Most popular questions from this chapter

A publisher estimates that a book will sell at the rate of \(16,000 e^{-0.8 t}\) books per year \(t\) years from now. Find the total number of books that will be sold by summing (integrating) this rate from 0 to \(\infty\).

a. Find the size of the permanent endowment needed to generate an annual \(\$ 1000\) forever at a continuous interest rate of \(10 \%\). b. At this same interest rate, the size of the fund needed to generate an annual \(\$ 1000\) for precisely 100 years is \(\int_{0}^{100} 1000 e^{-0.1 t} d t\). Evaluate this integral (it is not an improper integral), approximating your answer using a calculator. c. Notice that the cost for the first 100 years is almost the same as the cost forever. This illustrates again the principle that in endowments, the short term is expensive, but eternity is cheap.

Evaluate each improper integral or state that it is divergent. \(\int_{-\infty}^{x} \frac{e^{-x}}{\left(1+e^{-x}\right)^{3}} d x\)

Find the solution \(y(t)\) by recognizing each differential equation as determining unlimited, limited, or logistic growth, and then finding the constants. \(y^{\prime}=3 y-6 y^{2}\) \(y(0)=\frac{1}{6}\)

Let \(p(t)\) be the number of people in a city who have heard of a new product after \(t\) weeks of advertising. The city is of size \(1,000,000\), and \(p(t)\) grows at a rate proportional to the number of people in the city who have not heard of the product. If after 8 weeks 250,000 people have heard of the product, find a formula for \(p(t)\). Use your formula to estimate the number of people who will have heard of the product after 20 weeks of advertising.

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