Chapter 5: Problem 63
Choose the correct answer. \(\int e^{-1} d x=?\) a. \(\ln |e|+C\) b. \(\frac{1}{0} e^{0}+C\) c. \(e^{-1} x+C\)
Short Answer
Expert verified
The correct answer is c. \(e^{-1} x + C\).
Step by step solution
01
Identify the Integral
The problem asks us to find the indefinite integral of a constant function. The integrand in the problem is \(e^{-1}\), which is a constant because \(e\) is the base of the natural logarithm and \(-1\) is an exponent applied to it. Thus, we need to integrate \(e^{-1}\) with respect to \(x\).
02
Apply the Constant Rule of Integration
When integrating a constant, such as \(e^{-1}\), with respect to \(x\), we apply the constant rule of integration. This rule states that the integral of a constant \(a\) is \(a \cdot x + C\), where \(C\) is the constant of integration.
03
Calculate the Integral
Using the constant rule, the integral of \(e^{-1}\) with respect to \(x\) is \(e^{-1} x + C\). Here, \(e^{-1}\) is the constant and \(x\) is the variable of integration.
04
Choose the Correct Answer
Now, match the calculated result \(e^{-1} x + C\) with the options provided in the problem. The correct option is (c) \(e^{-1} x + C\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Constant Function Integration
When we talk about constant function integration, we're talking about integrating a function that doesn't change - in other words, it has a constant value across its entire domain. Think of it like drawing a perfectly straight horizontal line on a graph; no matter where you are, the function value remains the same.
This scenario applies to this exercise because we are dealing with the integral of a constant, specifically, the constant \( e^{-1} \).
This constant doesn't change with respect to the variable of integration, which in this case is \( x \).
When integrating a constant function, the result is straightforward: multiply the constant by the variable of integration and add the constant of integration, \( C \). This is why the integral of a constant \( a \) looks like \( a \cdot x + C \).
Remember, no matter how complex the constant might look (such as \( e^{-1} \)), the integration process remains simple and consistent.
This scenario applies to this exercise because we are dealing with the integral of a constant, specifically, the constant \( e^{-1} \).
This constant doesn't change with respect to the variable of integration, which in this case is \( x \).
When integrating a constant function, the result is straightforward: multiply the constant by the variable of integration and add the constant of integration, \( C \). This is why the integral of a constant \( a \) looks like \( a \cdot x + C \).
Remember, no matter how complex the constant might look (such as \( e^{-1} \)), the integration process remains simple and consistent.
Integration Techniques
Integration is a fundamental concept in calculus, often used to find areas under curves or solve differential equations. There are various integration techniques, each suited to different kinds of functions. Here are a few common ones:
So, while integration can sometimes require complex methods, integrating constants is usually a breeze.
- Substitution: Used primarily when the integral is complex and involves a composite function. It requires changing the variable of integration to simplify the integral.
- Integration by parts: Useful when an integral is the product of two functions. It relies on the principle from the product rule of differentiation.
- Partial fraction decomposition: A technique that breaks down complex rational expressions into simpler fractions that are easier to integrate.
So, while integration can sometimes require complex methods, integrating constants is usually a breeze.
Constant Rule of Integration
The constant rule of integration is one of the simplest and most frequently used rules in calculus. It's like a quick trick for turning a constant into its integrated form.
In this exercise, we see the constant \( e^{-1} \). Applying the constant rule means multiplying this constant by the variable of integration \( x \), and then adding an arbitrary constant \( C \). This gives us the integral \( e^{-1} x + C \).
In this exercise, we see the constant \( e^{-1} \). Applying the constant rule means multiplying this constant by the variable of integration \( x \), and then adding an arbitrary constant \( C \). This gives us the integral \( e^{-1} x + C \).
- Why the Constant Rule Works:
Integrating involves finding the antiderivative, or a function whose derivative is the original function. The derivative of \( a \cdot x \) is simply \( a \), which is why \( a \cdot x + C \) is the antiderivative of a constant \( a \). - The Constant \( C \):
It represents an unknown that accounts for any constant that disappears during differentiation. Since differentiation of a constant is zero, the constant of integration \( C \) allows for all possible antiderivatives.