Chapter 5: Problem 13
Find each indefinite integral. \(\int-5 x^{-1} d x\)
Short Answer
Expert verified
The indefinite integral is \( -5 \ln|x| + C \).
Step by step solution
01
Identify the Integral Form
The given integral is \( \int -5x^{-1} \, dx \). This represents the indefinite integral of a power of \( x \) where the exponent is -1.
02
Recall the Integral Formula for a Power of x
For most powers of \( x \), the formula \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \) can be used. However, when \( n = -1 \), this formula is not applicable because it would involve division by zero.
03
Use the Integral Formula for \( x^{-1} \)
When integrating \( x^{-1} \), also written as \( \frac{1}{x} \), the result is the natural logarithm: \( \int x^{-1} \, dx = \ln|x| + C \).
04
Compute the Integral
Apply the integral formula for \( x^{-1} \) to the given integral: \( \int -5x^{-1} \, dx = -5 \int x^{-1} \, dx = -5 \ln|x| + C \).
05
Write the Final Result
The indefinite integral of \( -5x^{-1} \) is \( -5 \ln|x| + C \), where \( C \) is the constant of integration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Rule for Integration
The Power Rule is a fundamental tool used in calculus to find the integral of functions in the form of a power of a variable. When you see an expression like \( x^n \), where \( n \) is a constant, the Power Rule provides an easy way to integrate it.
\[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \]
This formula adds 1 to the exponent \( n \) and adjusts the coefficient accordingly. It's a handy shortcut for quickly finding antiderivatives.
However, there are exceptions to this rule. When \( n = -1 \), the formula results in a division by zero, which is undefined. In this specific case, the Power Rule requires a different approach, which leads us to the concept involving the Natural Logarithm.
\[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \]
This formula adds 1 to the exponent \( n \) and adjusts the coefficient accordingly. It's a handy shortcut for quickly finding antiderivatives.
However, there are exceptions to this rule. When \( n = -1 \), the formula results in a division by zero, which is undefined. In this specific case, the Power Rule requires a different approach, which leads us to the concept involving the Natural Logarithm.
Natural Logarithm
The integral of \( x^{-1} \) is unique among the power functions because it involves the natural logarithm. Let's explore why this happens.
When faced with an integral that has \( x^{-1} \) or \( \frac{1}{x} \) as its integrand, the Power Rule doesn't apply. Instead, the integration formula involves the natural logarithm:
\[ \int x^{-1} \, dx = \ln |x| + C \]
This result expresses the area under the curve of \( 1/x \), leading to the natural appearance of the logarithmic function. The absolute value signs are crucial because the logarithm is undefined for non-positive values of \( x \), thus ensuring the expression is always defined for real values of \( x \).
This connection to natural logarithms makes the integral of \( x^{-1} \) an essential part of calculus, showing how different rules apply based on the power of \( x \). Understanding these subtleties helps in identifying which integration technique to use.
When faced with an integral that has \( x^{-1} \) or \( \frac{1}{x} \) as its integrand, the Power Rule doesn't apply. Instead, the integration formula involves the natural logarithm:
\[ \int x^{-1} \, dx = \ln |x| + C \]
This result expresses the area under the curve of \( 1/x \), leading to the natural appearance of the logarithmic function. The absolute value signs are crucial because the logarithm is undefined for non-positive values of \( x \), thus ensuring the expression is always defined for real values of \( x \).
This connection to natural logarithms makes the integral of \( x^{-1} \) an essential part of calculus, showing how different rules apply based on the power of \( x \). Understanding these subtleties helps in identifying which integration technique to use.
Constant of Integration
Integrating functions leads to a family of solutions, not just a single function, because of the constant of integration. When you compute an indefinite integral, like in our example, you will often see a \( + C \) at the end of the result. This \( C \) represents the constant of integration.
Why do we need a constant? Because the derivative of any constant is zero, adding or subtracting a constant doesn't change the derivative. Hence, when finding antiderivatives (or integrals), there are infinitely many functions that can have the same derivative, differing only by a constant.
Why do we need a constant? Because the derivative of any constant is zero, adding or subtracting a constant doesn't change the derivative. Hence, when finding antiderivatives (or integrals), there are infinitely many functions that can have the same derivative, differing only by a constant.
- This constant ensures that all possible solutions are captured.
- It signifies the "general solution" to the problem, acknowledging that without additional conditions (like initial values), we cannot pinpoint a unique solution.