Chapter 4: Problem 3
Find the derivative of each function. $$ f(x)=\ln x^{2} $$
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Chapter 4: Problem 3
Find the derivative of each function. $$ f(x)=\ln x^{2} $$
These are the key concepts you need to understand to accurately answer the question.
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For each function: a. Find the relative rate of change. b. Evaluate the relative rate of change at the given value(s) of \(t\). $$ f(t)=25 \sqrt{t-1}, \quad t=6 $$
A supply function \(S(p)\) gives the total amount of a product that producers are willing to supply at a given price \(p\). The elasticity of supply is defined as $$ E_{s}(p)=\frac{p \cdot S^{\prime}(p)}{S(p)} $$ Elasticity of supply measures the relative increase in supply resulting from a small relative increase in price. It is less useful than elasticity of demand, however, since it is not related to total revenue. Use the preceding formula to find the elasticity of supply for a supply function of the form \(S(p)=a e^{c p}\), where \(a\) and \(c\) are positive constants.
Each of the following functions is a company's price function, where \(p\) is the price (in dollars) at which quantity \(x\) (in thousands) will be sold. a. Find the revenue function \(R(x)\). [Hint: Revenue is price times quantity, \(p \cdot x .]\) b. Find the quantity and price that will maximize revenue. $$ p=4-\ln x $$
If a drug is injected intramuscularly, the concentration of the drug in the bloodstream after \(t\) hours will be $$ A(t)=\frac{c}{b-a}\left(e^{-a t}-e^{-b t}\right) $$ If the constants are \(a=0.4, b=0.6\), and \(c=0.1\), find the time of maximum concentration.
For each function: a. Find the relative rate of change. b. Evaluate the relative rate of change at the given value(s) of \(t\). $$ f(t)=e^{t^{2}}, \quad t=10 $$
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