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For each function, find a. \(f^{\prime \prime}(x)\) and b. \(f^{\prime \prime}(3)\). $$f(x)=\frac{x-1}{x}$$

Short Answer

Expert verified
\(f''(x) = -\frac{2}{x^3}\); \(f''(3) = -\frac{2}{27}\).

Step by step solution

01

Simplify the function

Rewrite the function in a simpler form to make differentiation easier. The given function is \( f(x) = \frac{x-1}{x} \). We can simplify it by dividing each term in the numerator by the denominator: \( f(x) = \frac{x}{x} - \frac{1}{x} = 1 - \frac{1}{x} \).
02

Find the first derivative

Differentiate \( f(x) \) with respect to \( x \). The derivative of \( 1 \) is \( 0 \), and the derivative of \( -\frac{1}{x} \) is \( \frac{1}{x^2} \) (using the power rule and the negative constant rule). Thus, \( f'(x) = 0 + \frac{1}{x^2} = \frac{1}{x^2} \).
03

Find the second derivative

Differentiate \( f'(x) = \frac{1}{x^2} \). This can be rewritten as \( f'(x) = x^{-2} \). Using the power rule, we find \( f''(x) = -2x^{-3} = -\frac{2}{x^3} \).
04

Evaluate the second derivative at x=3

Substitute \( x = 3 \) into \( f''(x) = -\frac{2}{x^3} \) to find \( f''(3) \). Compute: \( f''(3) = -\frac{2}{3^3} = -\frac{2}{27} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finding Derivatives
The process of finding a derivative involves calculating the rate at which a function changes at any given point. This is fundamental in calculus and serves as the groundwork for understanding changes in various scenarios. To find a derivative, you are essentially determining the slope or the steepness of the curve represented by the function.Differentiation is symbolized by the prime notation, like \( f'(x) \), or by using the Leibniz notation \( \frac{dy}{dx} \). The derivative tells us how much \( y \) changes as \( x \) changes. For example, given a function \( f(x) = \frac{x-1}{x} \), our first step is to differentiate it to find \( f'(x) \).Simplifying the function initially makes this process more straightforward. After simplifying \( f(x) = \frac{x-1}{x} \) to \( f(x) = 1 - \frac{1}{x} \), you find \( f'(x) = \frac{1}{x^2} \). This indicates how the function's value changes as \( x \) changes, reflecting how rapidly or slowly \( f(x) \) strengthens or weakens at each point.
Second Derivative
Once we have the first derivative, the second derivative gives additional insight. It indicates the behavior and shape of the graph of a function. Specifically, the second derivative tells us about the curvature or concavity of the function.Calculating the second derivative involves differentiating the first derivative. For the function in our example, with the first derivative \( f'(x) = \frac{1}{x^2} \), we rewrite it as \( x^{-2} \). Differentiating this with respect to \( x \) yields the second derivative: \( f''(x) = -2x^{-3} = -\frac{2}{x^3} \).The second derivative thus informs us whether the curve is concave up or concave down at different points. If \( f''(x) > 0 \), the graph is concave up, while \( f''(x) < 0 \) indicates it's concave down. By evaluating \( f''(x) \) at particular points, such as \( x = 3 \), we obtain \( f''(3) = -\frac{2}{27} \), suggesting that near \( x=3 \), the function curves downward.
Power Rule in Differentiation
The power rule is a crucial tool in differentiation. It's an easy and effective method to find the derivative of functions that are simple polynomial expressions. The rule states: if you have a function \( f(x) = x^n \), its derivative \( f'(x) \) is \( nx^{n-1} \).This rule is particularly useful when dealing with functions where terms are individual powers of \( x \). In our problem, while simplifying and differentiating \( f(x) = 1 - \frac{1}{x} \), applying the power rule to \( -x^{-1} \) resulted in the derivative \( \,\frac{1}{x^2} \). Similarly, it's used again to find \( f''(x) \) from \( f'(x) = x^{-2} \), resulting in \( f''(x) = -2x^{-3} \).By using the power rule, the cumbersome task of differentiation becomes straightforward, as it allows quickly finding first, second, or even higher-order derivatives for polynomials. This understanding simplifies many tasks in calculus, making analysis quicker and more efficient.

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Most popular questions from this chapter

The windchill index (revised in 2001 ) for a temperature of 32 degrees Fahrenheit and wind speed \(x\) miles per hour is \(W(x)=55.628-22.07 x^{0.16}\). a. Graph the windchill index on a graphing calculator using the window \([0,50]\) by \([0,40]\). Then find the windchill index for wind speeds of \(x=15\) and \(x=30\) mph. b. Notice from your graph that the windchill index has first derivative negative and second derivative positive. What does this mean about how successive 1-mph increases in wind speed affect the windchill index? c. Verify your answer to part (b) by defining \(1 / 2\) to be the derivative of \(y_{1}\) (using NDERIV), evaluating it at \(x=15\) and \(x=30\), and interpreting your answers.

The population of a city \(x\) years from now is predicted to be \(P(x)=\sqrt[4]{x^{2}+1}\) million people for \(1 \leq x \leq 5 .\) Find when the population will be growing at the rate of a quarter of a million people per year. [Hint: On a graphing calculator, enter the given population function in \(y_{1}\), use NDERIV to define \(1 / 2\) to be the derivative of \(y_{1}\), and graph both on the window \([1,5]\) by \([0,3]\). Then TRACE along \(y_{2}\) to find the \(x\) -coordinate (rounded to the nearest tenth of a unit) at which the \(y\) -coordinate is \(0.25\). You may have to \(Z O O M\) IN to find the correct \(x\) -value.]

Suppose that the quantity described is represented by a function \(f(t)\) where \(t\) stands for time. Based on the description: a. Is the first derivative positive or negative? b. Is the second derivative positive or negative? The population is growing increasingly fast.

Use the Generalized Power Rule to find the derivative of each function. $$f(x)=\frac{1}{\sqrt[3]{(3 x-1)^{2}}}$$

Using only straight lines, sketch a function that (a) is continuous everywhere and (b) is differentiable everywhere except at \(x=1\) and \(x=3\).

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