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Suppose that the quantity described is represented by a function \(f(t)\) where \(t\) stands for time. Based on the description: a. Is the first derivative positive or negative? b. Is the second derivative positive or negative? The economy is growing, but more slowly.

Short Answer

Expert verified
a. First derivative is positive. b. Second derivative is negative.

Step by step solution

01

Understanding the First Derivative

The first derivative of a function, denoted as \(f'(t)\), represents the rate of change of the function with respect to time. If the economy is growing, this indicates that \(f(t)\) is increasing over time. Therefore, the first derivative is positive, \(f'(t) > 0\).
02

Understanding the Second Derivative

The second derivative, denoted as \(f''(t)\), describes the rate of change of the first derivative, or the acceleration of the function. The statement 'the economy is growing, but more slowly' suggests that the rate of growth itself is decreasing. Thus, the second derivative is negative, \(f''(t) < 0\), indicating that the growth rate is slowing down.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate of Change
Understanding the rate of change is crucial because it tells us how a quantity is evolving over time. When we talk about the rate of change in a function related to time, we essentially refer to how fast something is increasing or decreasing. Consider a scenario where a function \( f(t) \) depicts the growth of an economy over time, \( t \). The first derivative \( f'(t) \) provides us with this crucial information.
  • If \( f'(t) > 0 \), it means that the quantity is increasing over time. In our economic context, this implies that the economy is expanding.
  • If \( f'(t) < 0 \), conversely, the economy would be contracting.
For the problem at hand, the economy is described as growing. This reflects a positive rate of change, \( f'(t) > 0 \), confirming that the overall trend is upward, even if that growth isn't accelerating.
Function Analysis
Examining a function through its derivatives provides deep insights into its behavior. This is crucial in fields like economics where understanding trends guides decision-making. Function analysis via derivatives helps us determine not just where a function is headed, but at what pace and how that pace itself is shifting.

First Derivative

The first derivative, \( f'(t) \), reveals the immediate rate of change of a function. If we consider it in terms of economic growth, a positive first derivative shows that the economy is expanding. It answers questions like: "Is the economy growing, and if so, how quickly?"

Second Derivative

The second derivative, \( f''(t) \), goes further. It actually reveals the change in the rate of growth itself. In our scenario, a negative second derivative tells us about a slowdown in the speed of growth. The economy still grows, but less robustly. This decrement in speed of growth ("growing, but more slowly") is vitally significant for long-term planning.
Economic Growth
Economic growth is a pivotal aspect showcasing how an economy progresses over time. Typically, it's gauged by indicators such as GDP growth. When an economy is described as growing, generally, it means more goods and services are being produced than before. Economic growth can be affected by numerous factors such as technological advancements, labor force changes, and policy shifts. In mathematical terms, it can be scrutinized using a function \( f(t) \) where time, \( t \), influences growth.

Implications of Positive and Negative Derivatives

  • A positive first derivative \( f'(t) > 0 \) indicates upward economic movement. More prosperity and resources might be available.
  • A negative second derivative \( f''(t) < 0 \) suggests that while growth continues, it may not be as rapid as before, slowing futuristic expectations.
Understanding these derivatives in relation to economic growth helps businesses, policymakers, and investors strategize effectively. A slowing growth rate, while still positive, might signal the need for intervention to sustain prosperity.

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Most popular questions from this chapter

Use the Generalized Power Rule to find the derivative of each function. $$f(x)=\sqrt[3]{1+\sqrt[3]{x}}$$

The population of a city \(x\) years from now is predicted to be \(P(x)=\sqrt[4]{x^{2}+1}\) million people for \(1 \leq x \leq 5 .\) Find when the population will be growing at the rate of a quarter of a million people per year. [Hint: On a graphing calculator, enter the given population function in \(y_{1}\), use NDERIV to define \(1 / 2\) to be the derivative of \(y_{1}\), and graph both on the window \([1,5]\) by \([0,3]\). Then TRACE along \(y_{2}\) to find the \(x\) -coordinate (rounded to the nearest tenth of a unit) at which the \(y\) -coordinate is \(0.25\). You may have to \(Z O O M\) IN to find the correct \(x\) -value.]

Suppose that the quantity described is represented by a function \(f(t)\) where \(t\) stands for time. Based on the description: a. Is the first derivative positive or negative? b. Is the second derivative positive or negative? The temperature is dropping increasingly rapidly.

Using only straight lines, sketch a function that (a) is continuous everywhere and (b) is differentiable everywhere except at \(x=1\) and \(x=3\).

a. Show that the definition of the derivative applied to the function \(f(x)=\sqrt{x}\) at \(x=0\) gives \(f^{\prime}(0)=\lim _{h \rightarrow 0} \frac{\sqrt{h}}{h}\). b. Use a calculator to evaluate the difference quotient \(\frac{\sqrt{h}}{h}\) for the following values of \(h\) : \(0.1,0.001\), and \(0.00001\). [Hint: Enter the calculation into your calculator with \(h\) replaced by \(0.1\), and then change the value of \(h\) by inserting zeros.] c. From your answers to part (b), does the limit exist? Does the derivative of \(f(x)=\sqrt{x}\) at \(x=0\) exist? d. Graph \(f(x)=\sqrt{x}\) on the window \([0,1]\) by \([0,1]\). Do you see why the slope at \(x=0\) does not exist?

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