Chapter 2: Problem 45
Use limits involving \(\pm \infty\) to describe the asymptotic behavior of each function from its graph. $$f(x)=\frac{1}{3-x}$$
Short Answer
Expert verified
Vertical asymptote at \(x = 3\); horizontal asymptote at \(y = 0\).
Step by step solution
01
Identifying the General Form
Recognize that the function \( f(x) = \frac{1}{3-x} \) is of the form \( f(x) = \frac{1}{g(x)} \) where \( g(x) = 3-x \). Thus, critical places to check are where \( g(x) = 0 \) and as \( x \) approaches \( \pm \infty \).
02
Finding Vertical Asymptotes
Set \( g(x) = 3-x = 0 \). Solve for \( x \): \( 3-x = 0 \Rightarrow x = 3 \). The function has a vertical asymptote at \( x = 3 \). This means as \( x \to 3^- \), \( f(x) \to -\infty \), and as \( x \to 3^+ \), \( f(x) \to +\infty \).
03
Analyzing Horizontal Asymptotic Behavior
To find horizontal asymptotes, examine \( \lim_{{x \to \pm\infty}} f(x) \). As \( x \to +\infty \) or \( x \to -\infty \), \( g(x) = 3-x \to -\infty \), making \( f(x) = \frac{1}{3-x} \to 0 \). Thus the horizontal asymptote of the graph is \( y = 0 \).
04
Confirming Overall Asymptotic Behavior
The vertical asymptote occurs at \( x = 3 \), and the horizontal asymptote occurs at \( y = 0 \), confirming the overall asymptotic behavior of the function \( f(x) = \frac{1}{3-x} \). This behavior is visible when sketching the graph, showing the approach towards these asymptotes.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertical Asymptote
A vertical asymptote is a vertical line that the graph of a function approaches but never touches. For the function \( f(x) = \frac{1}{3-x} \), we find the vertical asymptote by setting the denominator equal to zero: \( 3 - x = 0 \). Solving for \( x \), we get \( x = 3 \). This tells us that the function is undefined at \( x = 3 \) and will approach this line as \( x \) gets very close to 3 from either side. You can understand it like this:
- As \( x \to 3^- \), or when approaching 3 from the left, the function \( f(x) \to -\infty \).
- As \( x \to 3^+ \), or when approaching 3 from the right, the function \( f(x) \to +\infty \).
Horizontal Asymptote
Horizontal asymptotes show the behavior of a function as it moves towards extremely large positive or negative \( x \) values. For the function \( f(x) = \frac{1}{3-x} \), we need to understand how it behaves when \( x \to \pm \infty \). As \( x \to +\infty \) or \( x \to -\infty \), the expression \( 3-x \) becomes very large and negative, which makes the fraction \( \frac{1}{3-x} \) very small in magnitude. Therefore, we can say:
- \( \lim_{{x \to +\infty}} f(x) = 0 \).
- \( \lim_{{x \to -\infty}} f(x) = 0 \).
Limit at Infinity
Understanding limits at infinity helps us describe the end-behavior of functions. It refers to what happens to a function's values as \( x \) becomes very large and moves towards positive or negative infinity. For \( f(x) = \frac{1}{3-x} \), we have:
- \( \lim_{{x \to +\infty}} f(x) = 0 \) since the denominator \( 3-x \) becomes a large negative number.
- \( \lim_{{x \to -\infty}} f(x) = 0 \) as again \( 3-x \) still heads toward a large negative value, making the fraction tiny.