Chapter 2: Problem 40
Use the Generalized Power Rule to find the derivative of each function. $$g(z)=z^{2}\left(2 z^{3}-z+5\right)^{4}$$
Short Answer
Expert verified
The derivative is \(g'(z) = 2z (2z^3 - z + 5)^4 + 4z^2(2z^3 - z + 5)^3(6z^2 - 1)\).
Step by step solution
01
Identify the Two Functions
We need to identify the two functions involved in the product: \(u = z^2\) and \(v = (2z^3 - z + 5)^4\). The goal is to apply the Generalized Power Rule to find the derivative of \(g(z) = u\cdot v\).
02
Differentiate Using Product Rule
According to the Product Rule, the derivative of \(g(z) = u\cdot v\) is given by \(g'(z) = u'v + uv'\). Let's find \(u'\) and \(v'\).
03
Differentiate \(u = z^2\)
The derivative of \(u = z^2\) is \(u' = 2z\).
04
Differentiate \(v = (2z^3 - z + 5)^4\) Using the Generalized Power Rule
According to the Generalized Power Rule, if \(v = f(z)^n\), then \(v' = n\cdot f(z)^{n-1} \cdot f'(z)\). Here, \(f(z) = 2z^3 - z + 5\) and \(n = 4\). So, we find \(f'(z) = 6z^2 - 1\), and consequently, \(v' = 4\cdot (2z^3 - z + 5)^3 \cdot (6z^2 - 1)\).
05
Substitute and Simplify
Substituting the derivatives back into the Product Rule, we get \(g'(z) = (2z) \cdot (2z^3 - z + 5)^4 + z^2 \cdot 4(2z^3 - z + 5)^3(6z^2 - 1)\). Simplifying, \(g'(z) = 2z (2z^3 - z + 5)^4 + 4z^2(2z^3 - z + 5)^3(6z^2 - 1)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Product Rule
The Product Rule is a fundamental rule of calculus used for finding the derivative of a product of two functions. When you have two functions, say \( u(x) \) and \( v(x) \), and you want to find the derivative of their product \( g(x) = u(x)v(x) \), you use the product rule. The rule states that:
In our original exercise, our two functions are \( u = z^2 \) and \( v = (2z^3 - z + 5)^4 \). We apply the Product Rule to find the derivative of this product.
- \( g'(x) = u'(x)v(x) + u(x)v'(x) \)
In our original exercise, our two functions are \( u = z^2 \) and \( v = (2z^3 - z + 5)^4 \). We apply the Product Rule to find the derivative of this product.
- Differentiate each function individually.
- Use the formula to combine them as per the rule.
Differentiation
Differentiation is the process of finding the derivative of a function. A derivative represents the rate at which a function is changing at any given point and is a core concept in calculus. Let's break it down:
For \( u = z^2 \), the derivative is simply \( 2z \) following the basic power rule.
For \( v = (2z^3 - z + 5)^4 \), we used the Generalized Power Rule:
- The derivative of a simple polynomial function \( ax^n \) is \( anx^{n-1} \), where you bring the power down as a coefficient and subtract one from the original power.
- The Generalized Power Rule extends this further to functions raised to a power, such as \( (f(x))^n \).
For \( u = z^2 \), the derivative is simply \( 2z \) following the basic power rule.
For \( v = (2z^3 - z + 5)^4 \), we used the Generalized Power Rule:
- Express \( v \) as \( f(z)^n \) and then find the derivative \( v' = n \, f(z)^{n-1} \, f'(z) \).
- First, find \( f'(z) = 6z^2 - 1 \).
- Apply these to find \( v' = 4 \, (2z^3 - z + 5)^3 (6z^2 - 1) \).
Polynomial Functions
Polynomial functions are expressions consisting of variables and coefficients, involving only addition, subtraction, multiplication, and non-negative integer exponentiation of variables. They are very common in calculus and are known for their smooth, continuous curves. In our discussed exercise, we dealt with polynomial functions within a product:
- \( z^2 \), which is a straightforward polynomial with a degree of 2.
- \( 2z^3 - z + 5 \), another polynomial of degree 3 inside the larger expression.
- They follow specific rules for differentiation and integration, making them easier to manipulate mathematically.
- Their derivatives also form polynomial expressions, maintaining a consistent structure.