/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 Find \(f^{\prime}(x)\) by using ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find \(f^{\prime}(x)\) by using the definition of the derivative. $$f(x)=\frac{1}{x^{2}}$$

Short Answer

Expert verified
The derivative is \(f'(x) = \frac{-2}{x^3}\).

Step by step solution

01

Recall the Definition of the Derivative

The derivative of a function \(f(x)\) at a point \(x\) is given by the limit \(f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}\). We will use this definition to find \(f'(x)\) for \(f(x) = \frac{1}{x^2}\).
02

Substitute into the Derivative Formula

Substitute into the formula for the derivative: \(f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}\). This becomes \(f'(x) = \lim_{h \to 0} \frac{\frac{1}{(x+h)^2} - \frac{1}{x^2}}{h}\).
03

Simplify the Expression Inside the Limit

To combine the fractions in the numerator, find a common denominator: \((x+h)^2 x^2\). Thus, \(\frac{1}{(x+h)^2} - \frac{1}{x^2} = \frac{x^2 - (x+h)^2}{(x+h)^2 x^2}\).
04

Expand and Simplify the Numerator

Expand \((x+h)^2 = x^2 + 2xh + h^2\) and substitute: \(x^2 - (x^2 + 2xh + h^2) = -2xh - h^2\). Thus, the expression becomes \(\frac{-2xh - h^2}{(x+h)^2 x^2}\).
05

Factor and Simplify

Factor \(-h\) out of the numerator: \(-h(2x + h)\). So, the limit expression is \(\lim_{h \to 0} \frac{-h(2x+h)}{h(x+h)^2 x^2}\).
06

Cancel \(h\) and Evaluate the Limit

Cancel \(h\) in the numerator and denominator: \(\lim_{h \to 0} \frac{-(2x+h)}{(x+h)^2 x^2}\). Evaluate the limit as \(h\) approaches 0: \(\frac{-2x}{x^4} = \frac{-2}{x^3}\).
07

Write the Final Derivative

The derivative of \(f(x) = \frac{1}{x^2}\) is \(f'(x) = \frac{-2}{x^3}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Definition of the Derivative
The definition of the derivative is a fundamental concept in calculus. It allows us to calculate the rate of change of a function at any given point. Consider a function \( f(x) \), its derivative \( f'(x) \) is expressed as:
  • \( f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \)
The derivative represents the slope of the tangent line to the curve of the function at a particular \( x \)-value.

To find the derivative of a specific function, such as \( f(x) = \frac{1}{x^2} \), we substitute this function into the derivative formula mentioned above. The expression within the limit is then simplified to find \( f'(x) \). This step involves algebraic manipulation that usually includes simplifying complex expressions and factoring where necessary.
Understanding the definition of the derivative is vital as it forms the basis for many concepts in calculus, from analyzing motion to solving real-world problems involving rates of change.
Limits
Limits are a crucial concept in calculus, allowing us to understand the behavior of functions as they approach specific points. In the context of derivatives, limits are used to formalize the notion of instantaneous rate of change.

Here is how limits work with derivatives:
  • Evaluate the expression \( \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \) by finding how the expression behaves as \( h \) becomes very small.
This process often involves simplifying algebraic fractions or expressions to see the behavior as \( h \) approaches zero.

In our example of calculating the derivative of \( f(x) = \frac{1}{x^2} \), after substituting into the derivative formula, you need to use algebra to reduce the expression such that "\( h \)" can effectively approach zero without causing the expression to be undefined. Mastering limits is essential not only in derivatives but also in other areas of calculus like integration and sequence analysis.
Rational Functions
Rational functions, which are ratios of polynomials, often appear in calculus problems including derivative calculations. A rational function is any function of the form \( f(x) = \frac{P(x)}{Q(x)} \), where both \( P(x) \) and \( Q(x) \) are polynomials. These types of functions can sometimes be tricky due to their undefined points where \( Q(x) = 0 \).

When finding derivatives of rational functions using the definition, as in the problem \( f(x) = \frac{1}{x^2} \), you often need to:
  • Handle complex fractions by finding common denominators.
  • Simplify and cancel terms carefully to reveal behavior as variables approach certain limits (often zero).
Rational functions require careful algebraic manipulation to effectively apply limit processes for derivatives.

Understanding how to work with rational functions is crucial, not just in finding derivatives, but in broader calculus applications, such as analyzing asymptotic behavior and understanding function domains and ranges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The windchill index (revised in 2001 ) for a temperature of 32 degrees Fahrenheit and wind speed \(x\) miles per hour is \(W(x)=55.628-22.07 x^{0.16}\). a. Graph the windchill index on a graphing calculator using the window \([0,50]\) by \([0,40]\). Then find the windchill index for wind speeds of \(x=15\) and \(x=30\) mph. b. Notice from your graph that the windchill index has first derivative negative and second derivative positive. What does this mean about how successive 1-mph increases in wind speed affect the windchill index? c. Verify your answer to part (b) by defining \(1 / 2\) to be the derivative of \(y_{1}\) (using NDERIV), evaluating it at \(x=15\) and \(x=30\), and interpreting your answers.

Interest If $$\$ 1000$$ is deposited in a bank paying \(r \%\) interest compounded annually, 5 years later its value will be $$ V(r)=1000(1+0.01 r)^{5} \quad \text { dollars } $$ Find \(V^{\prime}(6)\) and interpret your answer. [Hint: \(r=6\) corresponds to \(6 \%\) interest.]

Velocity If a steel ball is dropped from the top of Taipei 101, the tallest building in the world, its height above the ground \(t\) seconds after it is dropped will be \(s(t)=1667-16 t^{2}\) feet (neglecting air resistance). a. How long will it take to reach the ground? [Hint: Find when the height equals zero.] b. Use your answer to part (a) to find the velocity with which it will strike the ground. (This is called the impact velocity.) c. Find the acceleration at any time \(t\).

True or False: \(\frac{d}{d x} f(5 x)=5 \cdot f^{\prime}(5 x)\).

Find functions \(f\) and \(g\) such that the given function is the composition \(f(g(x))\). $$\sqrt{x^{2}-9}+5$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.