Chapter 2: Problem 38
Find \(f^{\prime}(x)\) by using the definition of the derivative. $$f(x)=x^{4}$$$
Short Answer
Expert verified
The derivative \( f'(x) = 4x^3 \).
Step by step solution
01
Write the Definition of the Derivative
The derivative of a function \( f(x) \) at a point \( x \) is defined as \( f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h} \). This formula will be used to find the derivative of \( f(x) = x^4 \).
02
Substitute \( f(x) = x^4 \) into the Definition
Substitute the function \( f(x) = x^4 \) into the derivative definition: \[ f'(x) = \lim_{{h \to 0}} \frac{{(x+h)^4 - x^4}}{h} \].
03
Expand \((x+h)^4\)
Expand the expression \((x+h)^4\) using the binomial theorem: \((x+h)^4 = x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 \).
04
Simplify the Numerator
Substitute the expanded form back into the difference quotient: \[ f'(x) = \lim_{{h \to 0}} \frac{{x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 - x^4}}{h} \].Cancel out \( x^4 \): \[ f'(x) = \lim_{{h \to 0}} \frac{{4x^3h + 6x^2h^2 + 4xh^3 + h^4}}{h} \].
05
Factor Out \(h\) from the Numerator
Factor \(h\) out of the numerator: \[ f'(x) = \lim_{{h \to 0}} \frac{h(4x^3 + 6x^2h + 4xh^2 + h^3)}{h} \].Cancel \(h\) from the numerator and denominator: \[ f'(x) = \lim_{{h \to 0}} (4x^3 + 6x^2h + 4xh^2 + h^3) \].
06
Evaluate the Limit as \(h \to 0\)
As \(h\) approaches zero, the terms containing \(h\) vanish, resulting in: \[ f'(x) = 4x^3 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definition of Derivative
The derivative of a function is a fundamental concept in calculus, representing the rate at which a function changes at any given point. The formal definition involves a limit,
- Let's consider a function, denoted as \( f(x) \).
- The derivative, \( f'(x) \), is given by this limit expression: \( f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h} \).
Binomial Theorem
When dealing with powers of binomials, such as \((x+h)^n\), the binomial theorem becomes a useful tool. This theorem provides a formula to expand expressions of the form \((a + b)^n\), breaking them down into a series of terms. For example,
- With \((x+h)^4\), it expands into \( x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 \).
- Coefficients come from the binomial coefficients, which form the "Pascal's Triangle." The coefficients for \((x+h)^4\) are 1, 4, 6, 4, 1.
- The powers decrease for \( x \) and increase for \( h \), providing a smooth algebraic expansion to work with.
Limit Evaluation
Limits are a cornerstone of calculus and a critical part of finding derivatives. They allow us to handle values that approach a certain point. When evaluating limits during differentiation, especially with expressions like the difference quotient,
- You simplify expressions by canceling common terms, as was done with \( x^4 \) in the example.
- Factor out variables such as \( h \), enabling you to handle expressions more easily.
- As \( h \) approaches zero, any term still involving \( h \) vanishes, leaving only the terms independent of \( h \).
Polynomial Functions
Polynomial functions are expressions that involve variables raised to whole number powers, often combined with coefficients. Understanding how derivatives apply to them is crucial. In our specific case,
- The function is a simple polynomial, \( f(x) = x^4 \).
- When finding its derivative, the terms align with specific rules of calculus, particularly involving power functions.
- You calculate the derivative: any term \( ax^n \) results in \( anx^{n-1} \).