Chapter 2: Problem 19
Use the Generalized Power Rule to find the derivative of each function. $$w(z)=\sqrt[3]{9 z-1}$$
Short Answer
Expert verified
The derivative is \( w'(z) = \frac{3}{(9z-1)^{2/3}} \).
Step by step solution
01
Rewrite the function with exponents
The given function is \( w(z)=\sqrt[3]{9z-1} \). First, rewrite this radical expression by using exponents: \( w(z)=(9z-1)^{1/3} \).
02
Apply the Generalized Power Rule
Recall the Generalized Power Rule for derivatives: If \( f(z) = [g(z)]^n \), then the derivative \( f'(z) \) is \( n[g(z)]^{n-1}g'(z) \). Identify \( n=\frac{1}{3} \) and \( g(z)=9z-1 \).
03
Differentiate the inside function
Calculate the derivative of the inside function \( g(z)=9z-1 \). The derivative \( g'(z) \) is \( 9 \).
04
Apply the Generalized Power Rule
Using the results from Steps 2 and 3, apply the Generalized Power Rule:\[ w'(z) = \frac{1}{3}(9z-1)^{-2/3} \times 9 = 3(9z-1)^{-2/3} \].
05
Simplify the expression
Simplify the expression for the derivative:\[ w'(z) = \frac{3}{(9z-1)^{2/3}} \].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
In calculus, a derivative represents how a function changes as its input changes. It's like measuring the speed of a car, telling us how fast the position of the car changes with time. When given a function, such as the one in the exercise, the task of finding its derivative is asking us to determine the rate of change of that function with respect to its variable.
- Rate of Change: The derivative provides insight into how a quantity varies with another. In mathematical terms, it's often noted as \( f'(x) \) or \( \frac{df}{dx} \).
- Slope: For functions graphed as curves, the derivative at any point corresponds to the slope of the tangent line at that point.
Exponentiation
Exponentiation involves raising a number to the power of another. In other words, it tells you how many times to use a number in a multiplication. When dealing with calculus, particularly with the Generalized Power Rule, it's common to encounter functions expressed exponentially.
- Fractional Exponents: In this exercise, the exponent \( \frac{1}{3} \) represents the cube root of the inside function \( 9z-1 \). Rewriting roots as fractional exponents simplifies the differentiation process.
- Rules of Exponents: Products, powers, and roots follow specific mathematical rules that help transform expressions. Knowing these rules is essential for simplifying complex derivatives.
Calculus
Calculus is a broad field of mathematics focused on limits, functions, derivatives, integrals, and infinite series. It serves as a powerful tool to model and analyze change over time and space, forming the foundation for much of modern science and engineering.
- Differentiation: A core concept where we compute the derivative of functions, as we did using the Generalized Power Rule in our exercise.
- Generalized Power Rule: A crucial derivative rule used when differentiating functions raised to a power. This enables us to deal with a variety of exponent forms, including roots and fractional powers.